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<p><FONT class=normalfont><B><font color=blue>在shell程序中判断一个变量是不是由4个数字组成</font></B></FONT><BR><FONT class=smallfont color=#ff9900>2004-04-23 15:18 pm</FONT><BR><FONT class=normalfont>作者:作者<br>来自:Linux知识宝库<br>联系方式:无名<br><br>假设要判断的变量为name,则方法如下:<br>
asd=`echo $name | awk '{<br>
 if (substr($1,1,1)&gt;=0 && substr($1,1,1) &lt;=9 &&<br>
     substr($1,2,1) &gt;=0 && substr($1,2,1) &lt;=9 &&<br>
     substr($1,3,1) &gt;=0 && substr($1,3,1) &lt;=9 &&<br>
     substr($1,4,1) &gt;=0 && substr($1,4,1) &lt;=9)<br>
     printf("true");<br>
 else<br>
     printf("false");<br>
   <br>
}'`<br>
<br>
if [ asd = "true" ] #是数字<br>
。。。。<br>
elif  #不是数字<br>
。。。<br>
<br>
这个办法比较笨,不知其他人有没有更好的方法!<br>
<br>
<br>
<br>
在awk或case语句中对变量使用正则表达式 ^....$ 看其是否匹配就可以了。<br>
<br>
不好意思,应该用正则表达式[0-9][0-9][0-9][0-9]更简单。上面的方法想补救的话,可用<br>
<br>
#!/bin/sh<br>
# test<br>
expr $1 + 10(任意数字) &gt;/dev/null 2&gt;&1<br>
STATUS=$? (测试上条语句是否成功)<br>
if ["$STATUS"!="0"];then<br>
echo "$1 is composed of number"<br>
exit 0  <br>
执行test $name <br>
<br>
# cat zcc<br>
V=$1<br>
if ! echo $V|grep '.....' &gt;/dev/null<br>
then<br>
       if echo $V|grep '[0-9][0-9][0-9][0-9]' &gt;/dev/null<br>
       then<br>
               echo "ok"<br>
       else<br>
               echo "bad number"<br>
       fi<br>
else<br>
       echo 'bad number'<br>
fi<br>
# ./zcc 1234<br>
ok.<br>
# ./zcc 123333<br>
bad number<br>
# ./zcc 123<br>
bad number<br>
<br>
试试如何? <br>
<br>
为何不用case呢?更简单!<br>
case $a in<br>
    [0-9][0-9][0-9][0-9]) echo"变量是由4个数字组成";;<br>
    *) echo "变量不是由4个数字组成";;<br>
esac<br>
<br>
还是用CASE这种方法比较高。<br>
<br>
借这个帖子提醒大家,模式匹配用了awk,grep,case这些常用的,可别忘了还有expr啊。有时反而更直接。对于本例:<br>
expr $str : '^[0-9][0-9][0-9][0-9]$'<br>
如果值为4就是满足要求的串,否则为0。<br>
<br>
grep,awk,expr,case全用到了。<br>
讨论热烈的一个好贴。<br>
偶用 expr $1 : [0-9]* |grep 4<br>
<br>
valentine ,偷懒可不行啊,对于expr $1 : [0-9]*来说,如果$1="1234a"的话结果也是4。<br>
<br>
michaelds     确实逻辑严密啊。<br>
加个$限制一下好了。<br>
expr $1 : "[0-9]*$" |grep 4<br>
<br>
如果测试变量a<br>
test $a -gt 999 -a $a -lt 10000 2&gt;/dev/nul<br>
再判断$?就OK了<br>
</FONT><br>
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