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<p><FONT class=normalfont><B><font color=blue>用date获得前一天的日期</font></B></FONT><BR><FONT class=smallfont color=#ff9900>2004-04-23 15:18 pm</FONT><BR><FONT class=normalfont>作者：作者<br>来自：Linux知识宝库<br>联系方式：无名<br><br>好象有date 有-24 有+%y%m%d等，谢了。<br>
还有有办法获得3天前的日期吗？<br>
<br>
唉，在b shell没有这个用法了，要想用纯shell做几天前后的运算，只有自己想办法了，+%y%m%d用于控制输出格式，作用有限，要想做的话，参见这个帖子大家的发言：<br>
<br>
我的确在哪儿看到用一条命令就可以取昨天或明天的日期，<br>
参数中有-24或+24。没那么复杂<br>
<br>
好象用到了参数TZ=-24;export TZ什么的<br>
<br>
改变时区，应该可以实现，确实是个好方法。<br>
<br>
不会吧，你说的俺都明白了，你自己还不懂？<br>
<br>
date命令的显示是与环境变量TZ有关的<br>
看以下的命令操作，你应该便明白了，<br>
<br>
$#看当前时区<br>
$echo $TZ<br>
CST-8<br>
$#显示当前时间<br>
$date<br>
Mon Apr 2 15:48:36 CST 2002<br>
$#改变当前时区，<br>
TZ=CST+16;export TZ<br>
$#显示当前时间（中间未改变系统时间，但date命令的显示已为昨天）<br>
Mon Apr 1 15:48:33 CST 2002<br>
<br>
<br>
<br>
#!/bin/sh<br>
<br>
# ydate: A Bourne shell script that<br>
# prints yestarday's date<br>
# Output form: Month Day Year<br>
# From Focus on Unix: http://unix.about.com<br>
<br>
# Set the current month day and year.<br>
month=`date +%m`<br>
day=`date +%d`<br>
year=`date +%Y`<br>
<br>
# Add 0 to month. This is a<br>
# trick to make month an unpadded integer.<br>
month=`expr $month + 0`<br>
<br>
# Subtract one from the current day.<br>
day=`expr $day - 1`<br>
<br>
# If the day is 0 then determine the last<br>
# day of the previous month.<br>
if [ $day -eq 0 ]; then<br>
<br>
# Find the preivous month.<br>
month=`expr $month - 1` <br>
<br>
# If the month is 0 then it is Dec 31 of<br>
# the previous year.<br>
if [ $month -eq 0 ]; then<br>
month=12<br>
day=31<br>
year=`expr $year - 1` <br>
<br>
# If the month is not zero we need to find<br>
# the last day of the month.<br>
else<br>
case $month in<br>
1|3|5|7|8|10|12) day=31;;<br>
4|6|9|11) day=30;;<br>
2)<br>
if [ `expr $year % 4` -eq 0 ]; then<br>
if [ `expr $year % 400` -eq 0 ]; then<br>
day=29<br>
elif [ `expr $year % 100` -eq 0 ]; then<br>
day=28<br>
else<br>
day=29<br>
fi<br>
else<br>
day=28<br>
fi<br>
;;<br>
esac<br>
fi<br>
fi<br>
<br>
# Print the month day and year.<br>
echo $month $day $year<br>
exit 0 <br>
<br>
<br>
时区转换实在是太精妙了！：-)<br>
<br>
如果在shell中改了时区,执行完后,系统真正的时区还是正确的吗?<br>
<br>
回楼上：最好你要把TZ的设置该回去了。<br>
不过我在实践中用的方法是：<br>
如果你的主机能够连接到数据库的话，比如可以连接到SYBASE数据库，那就可以利用数据库里面计算时间的丰富的函数了，比如<br>
dateadd(day,getdate(),-1)<br>
就能得到最天的日期了<br>
<br>
因为这个贴子被版主盖过章，所以在此跟一下。<br>
最近经常看到有网友关于相对日期问题的贴子，这在shell下进行解决时比较头疼。现将我作的几个程序贴出来与大家分享。虽然是用c写的，把它们贴在这里，我想大家也不会太反对的。其中一个程序以前发表在sco版下，现在早已淹没在汪洋大海中了，无从查找。<br>
因为是早先刚学c时的作品，且英文又不行，故写出的程序比较难看，请大家别见笑。<br>
相关链接：<br>
<br>
<br>
<br>
date=`expr `date +%m%d` - 1`<br>
<br>
这儿有一个我写的计算昨天的函数，可能是纯shell中唯一的简单解决方案吧，要想将其应用在计算任意天前后，恐怕还是不太方便的，看看，能否满足？<br>
yesterday ()<br>
{<br>
_year=$1;_month=$2;_day=$3<br>
if [ $_day -eq 1 ];then<br>
if [ $_month -eq 1 ];then<br>
_year=`expr $_year - 1`<br>
_month=12<br>
else<br>
_month=`expr $_month - 1`<br>
fi<br>
_day=`echo `cal $_month $_year`|awk '{print $NF}'`<br>
else<br>
_day=`expr $_day - 1`<br>
fi<br>
echo "$_year $_month $_day"|awk '{if (length($2)==1) $2=0$2;if (length($3)==1) $3=0$3;print $1,$2,$3}'<br>
}<br>
<br>
<br>
<br>
unix 我没有试过，linux上可以用<br>
date --date "1 days ago"<br>
<br>
<br>
yy=`date +%Y` #Year yyyy<br>
mm=`date +%m` #Month mm<br>
dd=`date +%d` #Day dd<br>
<br>
if [ $dd = "01" ] #如果为月初则计算上月末的日期<br>
then<br>
lm=`expr $mm - 1 ` #lm 上月<br>
if [ $lm -eq 0 ]<br>
then lm=12<br>
fi<br>
case $Fm in<br>
1|3|5|7|8|10|12) Yesterday=31 ;;<br>
4|6|9|11) Yesterday=30 ;;<br>
2) #计算闰月<br>
if [ ` expr $yy % 4 ` -eq 0 -a `expr $yy % 100 ` -ne 0 -o ` expr $yy % 400 ` -eq 0 ]<br>
then Yesterday=29<br>
else Yesterday=28<br>
fi ;;<br>
esac<br>
<br>
else #如果不是月初的处理<br>
Yesterday=`expr $dd - 1 ` <br>
if [ $Yesterday -lt 10 ] ###上旬日期处理<br>
then Yesterday=0$Yesterday<br>
fi<br>
fi<br>
<br>
结果: today=20020301 yesterday=28 <br>
<br>
</FONT><br>
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