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mv $Ucase $Lcase<br>
done<br>
<br>
请大家完善并补充 <br>
<br>
for file in `ls`<br>
do<br>
mv $file `echo $file|tr "[A-Z]" "[a-z]"`<br>
done<br>
<br>
用awk也行 ：）<br>
#!/bin/sh<br>
for I in `ls` ;<br>
do<br>
C=$(echo $I|awk '{print toupper($I)}')<br>
mv $I $C<br>
done<br>
<br>
for i in *<br>
do<br>
a=`echo $i |tr '[a-z]' '[A-Z]'`<br>
cp $i $a<br>
echo $a<br>
rm -i $a<br>
done<br>
<br>
<br>
<br>
我的当前目录及其n级深度的子目录都是大写，我想改成小写。我用find . -exec file.sh {} ; 怎么每次都只能改一级的深度？非得用for 和cd/cd..才可以完成吗？<br>
<br>
<br>
<br>
find . -exec ...这样的命令肯定是递归搜索了（即深入n层目录）了，大半是你的file.sh有问题，无法处理带有目录的文件名，如：./a/file.txt文件在你的的脚本处理下，被处理成：mv ./a/file.txt ./A/FILE.TXT, ./A目录不存在当然mv不成功了。<br>
<br>
应该是在file.sh上出的问题，我是这么简单的做的：<br>
#!/bin/sh<br>
new=`echo $1|tr "[a-z]" "[A-Z]"`<br>
mv $1 $new<br>
<br>
这样的shell是基于find对深层目录处理时候是先从最深层处理的，现在看来find是从当前开始处理再至最深层的。<br>
那这样大小写转换的shell又该怎样写呢？ <br>
<br>
<br>
拆分后再转换<br>
#!/bin/sh<br>
dn=`dirname $1`<br>
fn=`basename $1`<br>
newfn=`echo $fn|tr "[a-z]" "[A-Z]"`<br>
mv $1 $dn/$newfn<br>
<br>
测试没通过。<br>
<br>
n=`dirname $1`<br>
newdn=`echo $dn|tr "[a-z]" "[A-Z]"`<br>
fn=`basename $1`<br>
newfn=`echo $fn|tr "[a-z]" "[A-Z]"`<br>
f1=$newdn/$fn<br>
f2=$newdn/$newfn<br>
<br>
if [ $f1 != $f2 ]<br>
then<br>
echo "$f1 $f2"<br>
mv $f1 $f2<br>
fi<br>
<br>
这个可以了。不过执行的时候这sh不能在被转化的目录中。<br>
应该这样：find . -exec ../mysh.sh {} ;<br>
<br>
<br>
<br>
<br>
<br>
下面引用由samhoo在 2002/10/24 03:33pm 发表的内容：<br>
dn=`dirname $1`<br>
newdn=`echo $dn|tr "" ""`<br>
fn=`basename $1`<br>
newfn=`echo $fn|tr "" ""`<br>
...<br>
<br>
<br>
<br>
呵呵，这个肯定也不行，不知道有没有人测试过？！<br>
原因是：你改过了目录的名字，所以$f1的目录$newdn是不存在的；还有如果有空目录出现，程序也是处理不了的。<br>
只有每次处理都重新读一次目录才可以，信乎？！<br>
<br>
俺测了，干活啊<br>
<br>
就是要把脚本放在所检验目录子外 <br>
<br>
<br>
<br>
<br>
下面引用由smileniu在 2002/12/17 02:51pm 发表的内容：<br>
呵呵，这个肯定也不行，不知道有没有人测试过？！<br>
原因是：你改过了目录的名字，所以$f1的目录$newdn是不存在的；还有如果有空目录出现，程序也是处理不了的。<br>
只有每次处理都重新读一次目录才可以，信乎？！<br>
<br>
<br>
<br>
<br>
分析的很对！一旦发生路径名改动，后面的都用不成了~~~<br>
<br>
可以改成这样就行了，<br>
<br>
代码：<br>
<br>
<br>
FILES=`find $1 | sort -r` <br>
<br>
for i in $FILES; do <br>
DIR=`dirname $i` <br>
BAS=`basename $i | tr '[a-z]' '[A-Z]'` <br>
bas=`echo $BAS | tr '[A-Z]' '[a-z]'` <br>
<br>
mv $DIR/$BAS $DIR/$bas <br>
done <br>
<br>
<br>
<br>
（不知为什么，后半部分居然没贴上，超出本页最大长度啦？）<br>
<br>
如果适当扩展一下，改成可以带参数，大写变小写，或者小写变大写，完整的如下<br>
<br>
代码：<br>
<br>
<br>
#!/bin/sh <br>
<br>
############################################################ <br>
# this script will change file name recursively with option <br>
# -u: locase to upcase <br>
# -l: upcase to locase <br>
############################################################ <br>
<br>
hint () { <br>
echo " Usage: $0 [-l|-u] DIR1 [DIR2 DIR3...] <br>
-l to lowcase <br>
-u to upcase" <br>
exit 1 <br>
} <br>
<br>
if test $# -lt 2; then <br>
echo "Too few arguments." <br>
hint <br>
fi <br>
<br>
while [ "$1" ]; do <br>
case $1 in <br>
-l) ACTION="lo" <br>
shift 1 <br>
;; <br>
-u) ACTION="up" <br>
shift 1 <br>
;; <br>
*) if test -d $1; then <br>
DIR="$DIR $1" <br>
else <br>
echo "no such directory --- $1" <br>
hint <br>
fi <br>
shift <br>
;; <br>
esac <br>
done <br>
<br>
# echo $ACTION <br>
# echo $DIR <br>
<br>
<br>
FOUND=`find $DIR | sort -r` <br>
<br>
for i in $FOUND; do <br>
DN=`dirname $i` <br>
BS=`basename $i` <br>
loBS=`echo $BS | tr '[A-Z]' '[a-z]'` <br>
upBS=`echo $BS | tr '[a-z]' '[A-Z]'` <br>
<br>
NAME1=$DN/$BS <br>
<br>
if [ "$ACTION" = "lo" ]; then <br>
NAME2=$DN/$loBS <br>
elif [ "$ACTION" = "up" ]; then <br>
NAME2=$DN/$upBS <br>
fi <br>
<br>
if [ "$NAME1" = "$NAME2" ]; then <br>
echo "****: $NAME1 ---x--- $NAME2 identical!" <br>
else <br>
echo "- renaming $NAME1 --> $NAME2" <br>
mv $NAME1 $NAME2 <br>
fi <br>
done <br>
<br>
是啊~<br>
<br>
其实仔细看了一下楼上的帖子，发现问题的所在就是 find 得到结果并不能直接拿来处理，因为它是自上而下的，而目录一旦改名，子目录就全抓瞎了。而经过排序后（先处理最深的目录，由里向外）就能用了。<br>
<br>
然后稍作修改，并加上一些参数，使之有一定的实用性。<br>
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