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<p><FONT class=normalfont><B><font color=blue>请问如何抽取特征字的下一行</font></B></FONT><BR><FONT class=smallfont color=#ff9900>2004-04-23 15:18 pm</FONT><BR><FONT class=normalfont>作者：作者<br>来自：Linux知识宝库<br>联系方式：无名<br><br>在AIX上想看看各process占用的内存大小，用svmon -P看。<br>
但是这样显示的内容太多了，我只需要出现"PID"那一行的下一行就够了。<br>
但是这一行里只有数据，没有特征字，只能依靠上一行的特征字来区分。<br>
用svmon -P|grep PID以后又应该怎么写呢？<br>
请指点。谢谢。<br>
<br>
编辑文件awkfile<br>
#!/usr/bin/awk -f<br>
<br>
BEGIN {temp=0}<br>
{if(temp!=0} print}<br>
{temp=index($0,"PID")}<br>
<br>
然后chmod 700 awkfile<br>
svmon -P | awkfile<br>
<br>
OVER!<br>
<br>
呵呵，我这里可是测试通过的<br>
<br>
with awk:<br>
svmon -P|awk '/PID/{getline;print}'<br>
<br>
with sed:<br>
svmon -P|sed '/PID/{N:p;}'<br>
<br>
果然比我的简单，pfpf<br>
用sed的，我在bash下怎么报错呀？<br>
<br>
我在cygwin的bash下试过.没问题啊,这么简单的语法.<br>
<br>
奇怪，{N:p;}是什么意思呀，手册里面没有找到<br>
<br>
N是到下一行,p是显示啊.<br>
<br>
呵呵，我明白了，你的N后面应该是;，但是写成:了，所以报错<br>
另外，错误虽然没有了<br>
结果有点问题<br>
<br>
$ps<br>
PID TTY TIME CMD<br>
24451 pts/8 0:00 csh<br>
25202 pts/8 0:00 ps<br>
$ps | sed '/PID/{N;p;}'<br>
PID TTY TIME CMD<br>
24451 pts/8 0:00 csh<br>
PID TTY TIME CMD<br>
24451 pts/8 0:00 csh<br>
25203 pts/8 0:00 ps<br>
25204 pts/8 0:00 sed<br>
<br>
why?<br>
<br>
要加 -n啊.<br>
<br>
very good! 非常实用。<br>
<br>
那不止下一行呢，比如下x行呢<br>
<br>
svmon -P|awk '/PID/ {for(i=0;i<x;i++) {getline;print}}'<br>
<br>
svmon -P|grep -n PID|awk '{cmd=sprintf("svmon -P|head -%d|tail -1",$1); system(cmd)}'<br>
请多指教<br>
<br>
我测试了一下Hell的脚本，是打印带有PID的那一行<br>
需求是打印PID行的下n行<br>
怎么样，改进一下吧<br>
<br>
svmon -P|grep -n PID|awk '{cmd=sprintf("svmon -P|head -%d|tail -%d",$1+1,n); system(cmd)}'<br>
<br>
svmon -P|grep -n PID|awk '{cmd=sprintf("svmon -P|head -%d|tail -%d",$1+n,n); system(cmd)}'<br>
<br>
grep has the function to get the line after the designed lines.<br>
<br>
grep -A2 PID yourfile<br>
<br>
grep -A2 PID yourfile |grep -v PID<br>
<br>
我的意思是不想要一个文件中包含特征字符串的行和其前后几行<br>
<br>
我想肯定有更简单的方法,请赐教<br>
<br>
#本程序将按给定的字符串在一文件中将其前后若干行删除<br>
#在h80机器上测试通过,对原有10万行的文本文件,删除其中8万行,<br>
#每个特征串删除前后共4行,即共有2万个指定字符串需删除,用时6分钟<br>
cp comlog021211 abab<br>
# M 前M行<br>
# N 后N行<br>
# string1 指定字符串<br>
M=3<br>
N=0<br>
string1="发送文件通讯失败"<br>
# count 为每次向下走的步数<br>
count=`expr $M + $N + 1`<br>
count_ini=0<br>
eval grep -n $string1 abab | awk -F ":" '{print $1}' > acac<br>
#为了删除最后一行,在后在加一行<br>
count_tmp=`tail -1 acac`<br>
echo $count_tmp >> acac<br>
#为bbb,pre赋值<br>
count_tmp=`head -1 acac`<br>
bbb=$count_tmp<br>
pre=`expr $count_tmp - $count`<br>
while read -r aaa<br>
do <br>
ccc=`expr $pre + $count`<br>
if [ $aaa != $ccc ]<br>
then<br>
CCC=`expr $bbb - $count_ini - $M`<br>
DDD=`expr $pre - $count_ini + $N`<br>
eval sed '${CCC},${DDD}d' abab > adad<br>
count_ini=`expr $count_ini + $DDD - $CCC + 1`<br>
cp adad abab<br>
bbb=$aaa<br>
fi<br>
pre=$aaa<br>
done < acac<br>
<br>
我想肯定有更简单的方法,请赐教<br>
<br>
#本程序将按给定的字符串在一文件中将其前后若干行删除<br>
#在h80机器上测试通过,对原有10万行的文本文件,删除其中8万行,<br>
#每个特征串删除前后共4行,即共有2万个指定字符串需删除,用时6分钟<br>
cp comlog021211 abab<br>
# M 前M行<br>
# N 后N行<br>
# string1 指定字符串<br>
M=3<br>
N=0<br>
string1="aaaaaaaaaaaaa"<br>
# count 为每次向下走的步数<br>
count=`expr $M + $N + 1`<br>
count_ini=0<br>
eval grep -n $string1 abab | awk -F ":" '{print $1}' > acac<br>
#为了删除最后一行,在后在加一行<br>
count_tmp=`tail -1 acac`<br>
echo $count_tmp >> acac<br>
#为bbb,pre赋值<br>
count_tmp=`head -1 acac`<br>
bbb=$count_tmp<br>
pre=`expr $count_tmp - $count`<br>
while read -r aaa<br>
do <br>
ccc=`expr $pre + $count`<br>
if [ $aaa != $ccc ]<br>
then<br>
CCC=`expr $bbb - $count_ini - $M`<br>
DDD=`expr $pre - $count_ini + $N`<br>
eval sed '${CCC},${DDD}d' abab > adad<br>
count_ini=`expr $count_ini + $DDD - $CCC + 1`<br>
cp adad abab<br>
bbb=$aaa<br>
fi<br>
pre=$aaa<br>
done < acac<br>
</FONT><br>
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