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<p><FONT class=normalfont><B><font color=blue>如何计算一个日期是星期几</font></B></FONT><BR><FONT class=smallfont color=#ff9900>2004-04-23 15:18 pm</FONT><BR><FONT class=normalfont>作者：作者<br>来自：Linux知识宝库<br>联系方式：无名<br><br>本来有这样的一个讨论的帖子,不小心被俺删掉了.觉得有些可惜,便写了一个贴上来.<br>
<br>
#!/bin/ksh<br>
getdayofweek()<br>
{<br>
# Function dayofweek<br>
# Sample input:20020703<br>
<br>
# Extract the month, day, and year<br>
year=`echo $1|cut -c1-4`<br>
month=`echo $1|cut -c5-6`<br>
day0=`echo $1|cut -c7-8`<br>
day=${day0#0}<br>
<br>
<br>
# Get the calendar line for the specified day of the month/year<br>
dline=`cal $month $year | sed 's// X /g; s/^/ /; s/$/ /' | grep " $day "`<br>
<br>
# Compute the day of the week<br>
IFS='<br>
'<br>
set $dline<br>
dow=1 for weekday do<br>
if [[ $day = $weekday ]]<br>
then<br>
break<br>
else<br>
(( dow = dow+1 ))<br>
fi<br>
done<br>
<br>
# Convert the numeric day of the week to a string<br>
case $dow in<br>
1) print Sun ;;<br>
2) print Mon ;;<br>
3) print Tue ;;<br>
4) print Wed ;;<br>
5) print Thu ;;<br>
6) print Fri ;;<br>
7) print Sat ;;<br>
*) print "wrong date" ;;<br>
esac<br>
}<br>
<br>
<br>
<br>
这样就可以了<br>
$ date -d "2002/08/13" "+%a"<br>
<br>
<br>
<br>
运行不过呀!<br>
<br>
<br>
斑竹的帖子确实有些问题。<br>
dline=`cal $month $year | sed 's// X /g; s/^/ /; s/$/ /' | grep " $day "`<br>
一行中的sed 参数有问题。<br>
<br>
是这样的，我对sed不是特别熟悉，可能是引号内有些问题吧<br>
<br>
<br>
我是测试过的呀.<br>
<br>
<br>
<br>
用它试试！<br>
get_whatdays()<br>
{<br>
year=`expr substr $1 1 4`<br>
month=`expr substr $1 5 2`<br>
day=`expr substr $1 7 2`<br>
b=`cal $month $year|wc -l`<br>
b=`expr $b - 1`<br>
a=`cal $month $year |awk -v day=$day -v jl=$b '{for i=1;i<=NF;i++){if($i==day){if (NR==$i){print $i-1}else{print 7-NF+i-1}}}}'`<br>
echo $a<br>
} <br>
<br>
{if($i==day){if (NR==$i){print $i-1}else{print 7-NF+i-1}}}}'`?<br>
测试过么？<br>
$i ----> i<br>
if ( i==day){if (NR==i){print i-1}..........<br>
<br>
<br>
我用过,没有问题.<br>
<br>
你贴出来的程序,for后少了一个(.<br>
且程序计算20020101时结果正确,计算20020103便出错了.<br>
<br>
噢！对不起，我没有试过这个时间段。<br>
真不好意思！！<br>
<br>
<br>
get_whatdays()<br>
{<br>
year=`expr substr $1 1 4`<br>
month=`expr substr $1 5 2`<br>
day=`expr substr $1 7 2`<br>
b=`cal $month $year|wc -l`<br>
b=`expr $b - 1`<br>
a=`cal $month $year |awk -v day=$day -v jl=$b '{for i=1;i<=NF;i++){if($i==day){if (NR==jl){print $i-1}else{print 7-NF+i-1}}}}'`<br>
echo $a<br>
} <br>
老斑，现在试试？<br>
<br>
<br>
得，又少了一个括号。<br>
<br>
<br>
我测试可以了,又安照偶的习惯改了一个valentine版.<br>
get_whatdays()<br>
{<br>
year=`echo $1|cut -c1-4`<br>
month=`echo $1|cut -c5-6`<br>
day=`echo $1|cut -c7-8`<br>
<br>
b=`cal $month $year|wc -l `<br>
cal $month $year |awk '{for(i=1;i<=NF;i++){if($i=='$day'){if (NR=='"$b"'-1<br>
){print i-1}else{print 7-NF+i-1}}}}'<br>
}<br>
<br>
<br>
斑竹，<br>
if (NR=='"$b"'-1<br>
){print $i-1}<br>
应该是<br>
if (NR=='"$b"'-1<br>
){print i-1}<br>
<br>
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<br>
$i是指第i个字段的值<br>
i是指i的值.<br>
按照原程序,应该是$i.<br>
<br>
对啊，<br>
函数返回值应该是0－6<br>
如果用$i-1，返回值超出0-6<br>
我用20020825测试了，返回值是24（25-1)<br>
应该是0(1-1)<br>
<br>
那应该是你说的对.我把它改过来.<br>
<br>
</FONT><br>
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