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<p><FONT class=normalfont><B><font color=blue>shell的问题</font></B></FONT><BR><FONT class=smallfont color=#ff9900>2004-04-23 15:18 pm</FONT><BR><FONT class=normalfont>作者:作者<br>来自:Linux知识宝库<br>联系方式:无名<br><br>公司是做软件开发的,程序员们的程序都要连接数据库进行调试。可是他们的程序死了以后<br>
数据库还是连接的,这样一来系统的资源(内存)就会被占用被耗尽,于是我就要经常去杀死已经死了的进程,可是这样很麻烦,我想编一个shell脚本,可不知道如何下手,就请大虾们帮帮忙了:-)<br>
例如下面这些 323 325 。。。。。。。。。335 337 这些进程不能被杀,主要是要杀后面有(LOCAL=NO)的进程。  我因该怎么做呀?<br>
oracle 14527     1  0 10:22:39 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
oracle 16865     1  0 11:01:46 ?        0:06 oraclextecs90 (LOCAL=NO)<br>
oracle 24346     1  0 00:00:52 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
oracle 24802     1  0 13:19:32 ?        0:03 oraclextecs90 (LOCAL=NO)<br>
oracle   323     1  0   Apr 12 ?        0:01 ora_pmon_xtecs90<br>
oracle   325     1  0   Apr 12 ?        1:35 ora_dbw0_xtecs90<br>
oracle   327     1  0   Apr 12 ?        2:45 ora_lgwr_xtecs90<br>
oracle   329     1  0   Apr 12 ?        2:45 ora_ckpt_xtecs90<br>
oracle   331     1  0   Apr 12 ?        1:54 ora_smon_xtecs90<br>
oracle   333     1  0   Apr 12 ?        0:00 ora_reco_xtecs90<br>
oracle   335     1  0   Apr 12 ?        0:00 ora_s000_xtecs90<br>
oracle   337     1  0   Apr 12 ?        0:00 ora_d000_xtecs90<br>
oracle 14229     1  0 10:17:29 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
oracle 23079     1  0 22:58:31 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
oracle  1117     1  0 14:45:31 ?        0:47 oraclextecs90 (LOCAL=NO)<br>
问题的补充:要杀连接已经超时了的进程(时间大于30分钟),而不是要杀死所有的LOCAL=NO进程。<br>
<br>
ps -e -o pid -o time -o args|grep LOCAL=NO&gt;/tmp/tmpfile  #把符合条件的进程放到临时文件中<br>
cat /tmp/tmpfile|while read LINE<br>
do<br>
TIME=`echo $LINE|awk '{print $2}'`       #取出进程运行时间<br>
TIME=`echo $TIME|awk -F: '{print $1}'`   #取出共运行多少分钟的数目<br>
TIME=`expr $TIME / 1`<br>
if [ $TIME -gt 30 ]                       #判断是否大于半小时<br>
then<br>
echo $LINE                   #将符合条件的进程信息输出<br>
fi<br>
done<br>
rm -f /tmp/tmpfile<br>
<br>
#现在有了进程信息,要杀要剐就随你便了! <br>
<br>
TIME说明:<br>
如果进程运行时间小于1小时,就显示为mm:ss。例如运行了15分钟23秒,就显示为15:23。<br>
如果进程运行时间大于1小时,就显示为hh:mm:ss。例如运行了1小时15分钟23秒,就显示为01:15:23。<br>
因为你每半小时就杀一回,我想你要杀的进程应该不会出现运行时间大于1小时的情况,所以就简化了程序。<br>
<br>
问题是个好问题。可干吗非要起一个帮帮忙的含糊名字呢?<br>
<br>
楼上的兄弟,我试了不行呀?<br>
<br>
使用sh<br>
<br>
我把你的脚本简化了,就让他运行一次结果报错<br>
expr: syntax error<br>
./kill_shell.or: [: -gt: unary operator expected<br>
简化的脚本是:<br>
ps -e -o pid -o time -o args|grep LOCAL=NO&gt;/tmp/tmpfile  <br>
cat /tmp/tmpfile| read LINE<br>
TIME=`echo $LINE|awk '{print $2}'`      <br>
TIME=`echo $TIME|awk -F: '{print $1}'`  <br>
TIME=`expr $TIME / 1`<br>
if [ $TIME -gt 30 ]                      <br>
then<br>
echo $LINE                <br>
fi<br>
<br>
<br>
<br>
不好意思,我一直都在BASH下,忘了进 SH 了现在可以了。<br>
你可以把awk的用法给我讲讲吗?<br>
<br>
运行脚本没有提示错误信息,可是好象还有问题:我把你的脚本改了一点:<br>
then<br>
echo $LINE (我给改成 KILL -9 &LINE)                <br>
fi<br>
先看了一下进程<br>
 oracle   337     1  0   Apr 12 ?        0:00 ora_d000_xtecs90<br>
 oracle   511     1  0   Apr 12 ?       12:59 /export/home/oracle/product/8.1.t<br>
   root 19197 16506  0 20:03:41 pts/5    0:00 grep oracle<br>
 oracle 18597     1  0 19:54:21 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 19061     1  0 20:01:19 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 18657     1  0 19:56:00 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
 oracle 18531     1  0 19:53:35 ?        0:02 oraclextecs90 (LOCAL=NO)<br>
 oracle 19196     1  1 20:03:40 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 15111     1  0 19:03:36 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
 oracle 16615     1  0 19:33:05 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 13892     1  0 18:14:50 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 18114     1  0 19:49:20 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 19188     1  2 20:03:28 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
 oracle 16257     1  0 19:28:25 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
# date<br>
Wed Apr 17 20:03:59 CST 2002<br>
运行了这个脚本后<br>
 oracle   331     1  0   Apr 12 ?        1:58 ora_smon_xtecs90<br>
 oracle   333     1  0   Apr 12 ?        0:00 ora_reco_xtecs90<br>
 oracle   335     1  0   Apr 12 ?        0:00 ora_s000_xtecs90<br>
 oracle   337     1  0   Apr 12 ?        0:00 ora_d000_xtecs90<br>
 oracle   511     1  0   Apr 12 ?       13:00 /export/home/oracle/product/8.1.t<br>
   root 19518 19440  0 20:10:36 pts/2    0:00 grep oracle<br>
 oracle 18597     1  0 19:54:21 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 19061     1  0 20:01:19 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
 oracle 18657     1  0 19:56:00 ?        0:01 oraclextecs90 (LOCAL=NO)<br>
 oracle 18531     1  1 19:53:35 ?        0:05 oraclextecs90 (LOCAL=NO)<br>
 oracle 15111     1  0 19:03:36 ?        0:02 oraclextecs90 (LOCAL=NO)<br>
 oracle 16615     1  0 19:33:05 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 13892     1  0 18:14:50 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 18114     1  0 19:49:20 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
 oracle 16257     1  0 19:28:25 ?        0:00 oraclextecs90 (LOCAL=NO)<br>
# date<br>
Wed Apr 17 20:11:08 CST 200<br>
没有变化,应该把 13892  15111 杀死的呀 为什么没有呀?<br>
<br>
我知道了。这个脚本,完成不了这个任务了,原因如下:<br>
TIME说明:<br>
 TIME 进程开始后占用CPU的时间的总和。而那些进程是在等待状态的不占用CPU(不可能大于30分钟!<br>
看来我还要在找方法了!<br>
<br>
<br>
<br>
终于成功了!!!!!!!!!!!!!!!!!!<br>
脚本如下:<br>
ps -e -o pid -o etime -o args|grep LOCAL=NO&gt;/tmp/tmpfile<br>
cat /tmp/tmpfile|while read LINE<br>
do<br>
TIME=`echo $LINE|awk '{print $2}'`<br>
TIME=`echo $TIME|awk -F: '{print $1}'`<br>
if [ $TIME -gt 30 ]<br>
then<br>
echo $LINE &gt;&gt; /tmp/tmpflie2<br>
fi<br>
done<br>
cut -c 1-5 /tmp/tmpfile2 |xargs -t -n1 kill -9<br>
rm -f /tmp/tmpfile<br>
rm -f /tmp/tmpfile2<br>
<br>
<br>
感谢 cpss  三少爷 kiss007 阿骁 跳舞牛仔 <br>
<br>
不错。<br>
俺来简化一下:<br>
<br>
ps -e -o pid -o etime -o args|grep LOCAL=NO|awk '(length($2&gt;5)||(substr($2,1,2)&gt;30){printf "kill -9 %s",$1}'|sh<br>
<br>
此处用length判断超过一小时的进程<br>
<br>
<br>
老大,括号好像不匹配。<br>
<br>
 <br>
不小心...<br>
我给改过来了。<br>
<br>
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