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<p><FONT class=normalfont><B><font color=blue>如何用date获得前一天的日期</font></B></FONT><BR><FONT class=smallfont color=#ff9900>2004-04-23 15:18 pm</FONT><BR><FONT class=normalfont>作者：作者<br>来自：Linux知识宝库<br>联系方式：无名<br><br>int  date8_add(char *date8,char ymd,int value,char *date8added);<br>
int  checkdate8(char *date8);<br>
long int days_from_8zeros(char *date8);<br>
int  get_data8_from_days(long int days,char *date8);<br>
<br>
<br>
//功能：计算某年月日前后一定年数（或月数、天数）的年月日<br>
//输入：<br>
//     1. date8 计算基准日期<br>
//     2. ymd   表示下一变量的单位  'y'-年  'm'-月  'd'-日<br>
//     3. value 偏移量：年数、月数、天数<br>
//输出：<br>
//     1. date8added 计算后结果<br>
//返回：<br>
//      0 成功<br>
//     -1 date8非法<br>
//     -2 ymd非法<br>
//     -3 value非法<br>
//     -4 转换后date8added的年份小于公元1年<br>
//     -5 转换后date8added的年份大于公元9999年<br>
//     -6 转换后date8added非法，例如得到结果为2002/02/30<br>
int  date8_add(char *date8,char ymd,int value,char *date8added)<br>
{<br>
   char strtmp[10];<br>
   long int days;<br>
   int c,vyear,vmonth,vday;<br>
   int errbz;<br>
<br>
   // 检查参数date8的合法性<br>
   errbz=checkdate8(date8);<br>
   if (errbz!=0) return(-1);<br>
<br>
   // 检查参数ymd的合法性<br>
   if ( ymd!='y' && ymd!='m' && ymd!='d') return(-2);<br>
<br>
   // 检查参数value的合法性(简单检查)<br>
   //if ( value &lt; -9999 || value &gt; 9999 ) return(-3);<br>
<br>
   // 当增加量为年数时，计算结果并返回<br>
   if (ymd=='y')<br>
   {<br>
      memset(strtmp,0,sizeof(strtmp));<br>
      memcpy(strtmp,date8+0,4);<br>
      sscanf(strtmp,"%d",&vyear);<br>
      vyear+=value;<br>
      if ( vyear&lt;1 )    return(-4); //小于公元1年<br>
      if ( vyear&gt;9999 ) return(-5); //大于公元9999年<br>
<br>
      strcpy(date8added,date8);<br>
      sprintf(strtmp,"%04d",vyear);<br>
      memcpy(date8added,strtmp,4);<br>
      errbz=checkdate8(date8added);<br>
      if (errbz!=0)     return(-6); //计算所得结果非法<br>
      return(0);<br>
   }<br>
<br>
   // 当增加量为月数时，计算结果并返回<br>
   if (ymd=='m')<br>
   {<br>
      vyear=0;<br>
      vmonth=0;<br>
      vday=0;<br>
     <br>
      memset(strtmp,0,sizeof(strtmp)); memcpy(strtmp,date8+0,4); sscanf(strtmp,"%d",&vyear);<br>
      memset(strtmp,0,sizeof(strtmp)); memcpy(strtmp,date8+4,2); sscanf(strtmp,"%d",&vmonth);<br>
      memset(strtmp,0,sizeof(strtmp)); memcpy(strtmp,date8+6,2); sscanf(strtmp,"%d",&vday);<br>
<br>
      vmonth=vyear*12+vmonth+value;<br>
      vmonth--;<br>
      vyear=vmonth/12;<br>
      vmonth=vmonth%12;<br>
      vmonth++;<br>
<br>
      if (vyear&lt;1) return(-4);<br>
      if (vyear&gt;9999) return(-5);<br>
      sprintf(date8added,"%04d%02d%02d",vyear,vmonth,vday);<br>
      errbz=checkdate8(date8added);<br>
      if (errbz!=0) return(-6);<br>
      return(0);<br>
   }<br>
<br>
   // 当增加量为天数时，计算结果并返回<br>
   if (ymd=='d')<br>
   {<br>
      days=days_from_8zeros(date8);<br>
      days+=value;<br>
      if (days&lt;=366) return(-4);    //年号为0000<br>
      if (days&gt;3652425) return(-5); //年号超出9999<br>
      errbz=get_data8_from_days(days,date8added);<br>
      if (errbz!=0) return(-1);<br>
      return(0);<br>
   }<br>
<br>
}<br>
<br>
<br>
//检查日期YyyyMmdd<br>
//输入：date8 日期字符串<br>
//返回：0-正确  -1-错误<br>
int  checkdate8(char *date8)<br>
{<br>
   int c;<br>
   int errdate=0;<br>
   char str_year[5]="";<br>
   char str_mon[3]="";<br>
   char str_day[3]="";<br>
   int int_year,int_mon,int_day;<br>
   int leap_year;          // 1-闰年  0-不是闰年<br>
<br>
   errdate=0;<br>
   if ( strlen(date8) != 8 ) errdate=1;<br>
   if (errdate!=1)<br>
   {<br>
      for (c=0;c&lt;10;c++)<br>
      {<br>
        if (date8[c]==' ') errdate=1;<br>
      }<br>
      if ( date8[0] &lt; '0'  || date8[0] &gt;  '9' ) errdate=1;<br>
      if ( date8[1] &lt; '0'  || date8[1] &gt;  '9' ) errdate=1;<br>
      if ( date8[2] &lt; '0'  || date8[2] &gt;  '9' ) errdate=1;<br>
      if ( date8[3] &lt; '0'  || date8[3] &gt;  '9' ) errdate=1;<br>
      if ( date8[4] &lt; '0'  || date8[4] &gt;  '9' ) errdate=1;<br>
      if ( date8[5] &lt; '0'  || date8[5] &gt;  '9' ) errdate=1;<br>
      if ( date8[6] &lt; '0'  || date8[6] &gt;  '9' ) errdate=1;<br>
      if ( date8[7] &lt; '0'  || date8[7] &gt;  '9' ) errdate=1;<br>
   }<br>
<br>
   if (errdate!=1)<br>
   {<br>
      str_year[0]=date8[0]; str_year[1]=date8[1];<br>
         str_year[2]=date8[2]; str_year[3]=date8[3];<br>
         str_year[4]='</FONT><br>
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