📄 ex9_10.cpp
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#include<fstream.h> //<fstream.h>包含<iostream.h>
#include<string.h>
#include<iomanip.h>
class inventory{
char Description[20];
char No[10];
int Quantity;
double Cost;
double Retail;
public:
inventory(char* ="#",char* ="0",int =0,double =0,double =0);
void display();
Bdatatofile(ofstream&dist);//这里直接用文件流类
Bdatafromfile(ifstream&dist);
};
inventory::inventory(char *des,char *no,int quan,double cost,double ret){
strcpy(Description,des);
strcpy(No,no);
Quantity=quan;
Cost=cost;
Retail=ret;
}
void inventory::display(){
cout.setf(ios::left);
cout<<setw(20)<<Description<<setw(10)<<No;
cout.unsetf(ios::left);//要改为右对齐,先清左对齐
cout.setf(ios::right);
cout<<setw(10)<<Quantity<<setw(10)<<Cost<<setw(10)<<Retail<<endl;
}
inventory::Bdatatofile(ofstream&dist){
dist.write(Description,20);
dist.write(No,10);
dist.write((char*)&Quantity,sizeof(int));
dist.write((char*)&Cost,sizeof(double));
dist.write((char*)&Retail,sizeof(double));
}
inventory::Bdatafromfile(ifstream&sour){
sour.read(Description,20);
sour.read(No,10);
sour.read((char*)&Quantity,sizeof(int));
sour.read((char*)&Cost,sizeof(double));
sour.read((char*)&Retail,sizeof(double));
}//由此可见读和写是完全对称的过程,次序决不能错
void main(){
inventory car1("夏利2000","805637928",156,80000,105000),car2;
inventory motor1("金城125","93612575",302,10000,13000),motor2;
ofstream ddatafile("d:\\Ex9_10.data",ios::out|ios::binary);
car1.Bdatatofile(ddatafile);
motor1.Bdatatofile(ddatafile);
cout<<"对象car1:"<<endl;
car1.display();
cout<<"对象motor1:"<<endl;
motor1.display();
cout<<"对象car2:"<<endl;
car2.display();
cout<<"对象motor2:"<<endl;
motor2.display();
ddatafile.close();
ifstream sdatafile("d:\\Ex9_10.data",ios::in|ios::binary);//重新打开文件,从头读取数据
car2.Bdatafromfile(sdatafile);//从文件读取数据拷贝到对象car2
if(sdatafile.eof()==0) cout<<"读文件成功"<<endl;
cout<<"对象car2:"<<endl;
car2.display();
motor2.Bdatafromfile(sdatafile);//继续从文件读取数据拷贝到对象motor2
if(sdatafile.eof()==0) cout<<"读文件成功"<<endl;
cout<<"对象motor2:"<<endl;
motor2.display();
sdatafile.close();
}
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