📄 bestpos.m
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%%%% Find the best position for partitioning sequences %%%%%
%%%%%% belong in this node of tree %%%%%
%%%%%% %%%%%
%%%%%% Kostas Blekas, 19 Dec. 2001 %%%%%
%%%%%% please contact at kblekas@cc.uoi.gr in case of problems %%
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [r,deg] = bestpos(XI,ni,W,thres)
for i=1:ni
st = XI(i,:);
k1 = 0;
for j = 1:ni
k1 = k1 + 1.0 - size(find(st==XI(j,:)),2)/W;
end
b(i) = k1;
end
[min1,ind] = min(b);
r = ind;
deg = 0;
for i=1:ni
dist(i) = 1.0 - size(find(XI(r,:)==XI(i,:)),2)/W;
end
if (size(find(dist<thres),2)==ni)
deg = 1;
end
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