numerictest.cpp

来自「Think in C++ 第二版源码」· C++ 代码 · 共 43 行

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//: C21:NumericTest.cpp

// From Thinking in C++, 2nd Edition

// Available at http://www.BruceEckel.com

// (c) Bruce Eckel 1999

// Copyright notice in Copyright.txt

#include "PrintSequence.h"

#include <numeric>

#include <algorithm>

#include <iostream>

#include <iterator>

#include <functional>

using namespace std;



int main() {

  int a[] = { 1, 1, 2, 2, 3, 5, 7, 9, 11, 13 };

  const int asz = sizeof a / sizeof a[0];

  print(a, a + asz, "a", " ");

  int r = accumulate(a, a + asz, 0);

  cout << "accumulate 1: " << r << endl;

  // Should produce the same result:

  r = accumulate(a, a + asz, 0, plus<int>());

  cout << "accumulate 2: " << r << endl;

  int b[] = { 1, 2, 3, 4, 1, 2, 3, 4, 1, 2 };

  print(b, b + sizeof b / sizeof b[0], "b", " ");

  r = inner_product(a, a + asz, b, 0);

  cout << "inner_product 1: " << r << endl;

  // Should produce the same result:

  r = inner_product(a, a + asz, b, 0, 

    plus<int>(), multiplies<int>());

  cout << "inner_product 2: " << r << endl;

  int* it = partial_sum(a, a + asz, b);

  print(b, it, "partial_sum 1", " ");

  // Should produce the same result:

  it = partial_sum(a, a + asz, b, plus<int>());

  print(b, it, "partial_sum 2", " ");

  it = adjacent_difference(a, a + asz, b);

  print(b, it, "adjacent_difference 1"," ");

  // Should produce the same result:

  it = adjacent_difference(a, a + asz, b, 

    minus<int>());

  print(b, it, "adjacent_difference 2"," ");

} ///:~

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