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<TITLE>第 2 章 线性表</TITLE>
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<B><FONT SIZE=3><P ALIGN="JUSTIFY">1. </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>联接定长顺序存储的串算法</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> Status</B> Concat ( SString <B>&</B>T, SString S1, SString S2 ) </FONT><B><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>{</P>
</B></FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> // </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>用</FONT><FONT SIZE=3> <I>T</I> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>返回由</FONT><FONT SIZE=3> <I>S</I>1 </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>和</FONT><FONT SIZE=3> <I>S</I>2 </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>联接而成的新串。</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY">// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>如果没有截断，则返回</FONT><FONT SIZE=3> TRUE</FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>，否则返回</FONT><FONT SIZE=3> FALSE</FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>。</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY">// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>假定以下标为</FONT><FONT SIZE=3> 0 </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>的数组分量存放串实际长度。</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> <B>if</B> ( S1[0] + S2[0] <= MAXSTRLEN ) </FONT><B><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>{</FONT><FONT SIZE=3> 		</B>// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>没有截断</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3>T[ 1.. S1[0] ] = S1[ 1.. S1[0] ];</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3>T[ S1[0] + 1.. S1[0] + S2[0] ] = S2[ 1.. S2[0] ];</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>		</FONT><FONT SIZE=3>T[0] = S1[0] + S2[0]; </P><DIR>
<P ALIGN="JUSTIFY">uncut = TURE;</P></DIR>
<P ALIGN="JUSTIFY"> </FONT><B><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>}</FONT><FONT SIZE=3> </B>// if </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>结束</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> <B>else if </B>( S1[0] < MAXSTRLEN ) </FONT><B><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>{</FONT><FONT SIZE=3> 			</B>// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>截断</FONT><FONT SIZE=3> <I>S</I>2</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3>T[ 1.. S1[0] ] = S1[ 1.. S1[0] ];</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3>T[ S1[0] + 1.. MAXSTRLEN ] = S2[ 1.. MAXSTRLEN – S1[0] ];</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>		</FONT><FONT SIZE=3>T[0] = MAXSTRLEN; </P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>		</FONT><FONT SIZE=3>uncut = FALSE;</P>
<P ALIGN="JUSTIFY"> </FONT><B><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>}</FONT><FONT SIZE=3> </B>// else if </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>结束</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> <B>else if </B>( S1[0] = MAXSTRLEN )<B> { 			</B>// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>截断（仅取</FONT><FONT SIZE=3> <I>S</I>1</FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>）</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>		</FONT><FONT SIZE=3>T[ 0.. MAXSTRLEN ] = S1[ 0 .. MAXSTRLEN ];</P><DIR>
<P ALIGN="JUSTIFY">// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>因为</FONT><FONT SIZE=3> T[0] = = S1[0] = = MAXSTRLEN</P></DIR>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3>uncut = FALSE;</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	<B>}</FONT><FONT SIZE=3> </B>// else if </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>结束</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> <B>else { 									</B>// </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>若</FONT><FONT SIZE=3> S1[0] > MAXSTRLEN</FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>，截断</FONT><FONT SIZE=3> <I>S</I>1</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3>T[ 1.. MAXSTRLEN ] = S1[ 1.. MAXSTRLEN ];</P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>		</FONT><FONT SIZE=3>T[0] = MAXSTRLEN; </P>
<P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>		</FONT><FONT SIZE=3>uncut = FALSE;</P>
<B><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>}</FONT><FONT SIZE=3> </B>// else </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>结束</P>
</FONT><FONT SIZE=3><P ALIGN="JUSTIFY"> </FONT><FONT FACE="宋体" LANG="ZH-CN" SIZE=3>	</FONT><FONT SIZE=3> <B>return</B> uncut;</P>
</FONT><B><FONT FACE="宋体" LANG="ZH-CN" SIZE=3><P ALIGN="JUSTIFY">}</B></FONT><FONT SIZE=3> // Concat</P></FONT></BODY>
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