📄 3-3.cpp
字号:
#include<iostream.h>
void main()
{
int year,mon,days,leap;
cout<<"年 月:";
cin>>year>>mon;
switch(mon)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:days=31;
break;
case 4:
case 6:
case 9:
case 11:days=30;
break;
case 2:if(year%400==0)
leap=1;
else if(year%4==0&&year%100!=0)
leap=1;
else leap=0l;
if(leap) days=29;
else days=28;
}
cout<<year<<"年"<<mon<<"月的天数为:"<<days<<endl;
}
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