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📄 jquant2.c

📁 linux下的flash播放器源程序
💻 C
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  if (c0max > c0min)    for (c0 = c0min; c0 <= c0max; c0++)      for (c1 = c1min; c1 <= c1max; c1++) {	histp = & histogram[c0][c1][c2min];	for (c2 = c2min; c2 <= c2max; c2++)	  if (*histp++ != 0) {	    boxp->c0min = c0min = c0;	    goto have_c0min;	  }      } have_c0min:  if (c0max > c0min)    for (c0 = c0max; c0 >= c0min; c0--)      for (c1 = c1min; c1 <= c1max; c1++) {	histp = & histogram[c0][c1][c2min];	for (c2 = c2min; c2 <= c2max; c2++)	  if (*histp++ != 0) {	    boxp->c0max = c0max = c0;	    goto have_c0max;	  }      } have_c0max:  if (c1max > c1min)    for (c1 = c1min; c1 <= c1max; c1++)      for (c0 = c0min; c0 <= c0max; c0++) {	histp = & histogram[c0][c1][c2min];	for (c2 = c2min; c2 <= c2max; c2++)	  if (*histp++ != 0) {	    boxp->c1min = c1min = c1;	    goto have_c1min;	  }      } have_c1min:  if (c1max > c1min)    for (c1 = c1max; c1 >= c1min; c1--)      for (c0 = c0min; c0 <= c0max; c0++) {	histp = & histogram[c0][c1][c2min];	for (c2 = c2min; c2 <= c2max; c2++)	  if (*histp++ != 0) {	    boxp->c1max = c1max = c1;	    goto have_c1max;	  }      } have_c1max:  if (c2max > c2min)    for (c2 = c2min; c2 <= c2max; c2++)      for (c0 = c0min; c0 <= c0max; c0++) {	histp = & histogram[c0][c1min][c2];	for (c1 = c1min; c1 <= c1max; c1++, histp += HIST_C2_ELEMS)	  if (*histp != 0) {	    boxp->c2min = c2min = c2;	    goto have_c2min;	  }      } have_c2min:  if (c2max > c2min)    for (c2 = c2max; c2 >= c2min; c2--)      for (c0 = c0min; c0 <= c0max; c0++) {	histp = & histogram[c0][c1min][c2];	for (c1 = c1min; c1 <= c1max; c1++, histp += HIST_C2_ELEMS)	  if (*histp != 0) {	    boxp->c2max = c2max = c2;	    goto have_c2max;	  }      } have_c2max:  /* Update box volume.   * We use 2-norm rather than real volume here; this biases the method   * against making long narrow boxes, and it has the side benefit that   * a box is splittable iff norm > 0.   * Since the differences are expressed in histogram-cell units,   * we have to shift back to JSAMPLE units to get consistent distances;   * after which, we scale according to the selected distance scale factors.   */  dist0 = ((c0max - c0min) << C0_SHIFT) * C0_SCALE;  dist1 = ((c1max - c1min) << C1_SHIFT) * C1_SCALE;  dist2 = ((c2max - c2min) << C2_SHIFT) * C2_SCALE;  boxp->volume = dist0*dist0 + dist1*dist1 + dist2*dist2;    /* Now scan remaining volume of box and compute population */  ccount = 0;  for (c0 = c0min; c0 <= c0max; c0++)    for (c1 = c1min; c1 <= c1max; c1++) {      histp = & histogram[c0][c1][c2min];      for (c2 = c2min; c2 <= c2max; c2++, histp++)	if (*histp != 0) {	  ccount++;	}    }  boxp->colorcount = ccount;}LOCAL(int)median_cut (j_decompress_ptr cinfo, boxptr boxlist, int numboxes,	    int desired_colors)/* Repeatedly select and split the largest box until we have enough boxes */{  int n,lb;  int c0,c1,c2,cmax;  register boxptr b1,b2;  while (numboxes < desired_colors) {    /* Select box to split.     * Current algorithm: by population for first half, then by volume.     */    if (numboxes*2 <= desired_colors) {      b1 = find_biggest_color_pop(boxlist, numboxes);    } else {      b1 = find_biggest_volume(boxlist, numboxes);    }    if (b1 == NULL)		/* no splittable boxes left! */      break;    b2 = &boxlist[numboxes];	/* where new box will go */    /* Copy the color bounds to the new box. */    b2->c0max = b1->c0max; b2->c1max = b1->c1max; b2->c2max = b1->c2max;    b2->c0min = b1->c0min; b2->c1min = b1->c1min; b2->c2min = b1->c2min;    /* Choose which axis to split the box on.     * Current algorithm: longest scaled axis.     * See notes in update_box about scaling distances.     */    c0 = ((b1->c0max - b1->c0min) << C0_SHIFT) * C0_SCALE;    c1 = ((b1->c1max - b1->c1min) << C1_SHIFT) * C1_SCALE;    c2 = ((b1->c2max - b1->c2min) << C2_SHIFT) * C2_SCALE;    /* We want to break any ties in favor of green, then red, blue last.     * This code does the right thing for R,G,B or B,G,R color orders only.     */#if RGB_RED == 0    cmax = c1; n = 1;    if (c0 > cmax) { cmax = c0; n = 0; }    if (c2 > cmax) { n = 2; }#else    cmax = c1; n = 1;    if (c2 > cmax) { cmax = c2; n = 2; }    if (c0 > cmax) { n = 0; }#endif    /* Choose split point along selected axis, and update box bounds.     * Current algorithm: split at halfway point.     * (Since the box has been shrunk to minimum volume,     * any split will produce two nonempty subboxes.)     * Note that lb value is max for lower box, so must be < old max.     */    switch (n) {    case 0:      lb = (b1->c0max + b1->c0min) / 2;      b1->c0max = lb;      b2->c0min = lb+1;      break;    case 1:      lb = (b1->c1max + b1->c1min) / 2;      b1->c1max = lb;      b2->c1min = lb+1;      break;    case 2:      lb = (b1->c2max + b1->c2min) / 2;      b1->c2max = lb;      b2->c2min = lb+1;      break;    }    /* Update stats for boxes */    update_box(cinfo, b1);    update_box(cinfo, b2);    numboxes++;  }  return numboxes;}LOCAL(void)compute_color (j_decompress_ptr cinfo, boxptr boxp, int icolor)/* Compute representative color for a box, put it in colormap[icolor] */{  /* Current algorithm: mean weighted by pixels (not colors) */  /* Note it is important to get the rounding correct! */  my_cquantize_ptr cquantize = (my_cquantize_ptr) cinfo->cquantize;  hist3d histogram = cquantize->histogram;  histptr histp;  int c0,c1,c2;  int c0min,c0max,c1min,c1max,c2min,c2max;  long count;  long total = 0;  long c0total = 0;  long c1total = 0;  long c2total = 0;    c0min = boxp->c0min;  c0max = boxp->c0max;  c1min = boxp->c1min;  c1max = boxp->c1max;  c2min = boxp->c2min;  c2max = boxp->c2max;    for (c0 = c0min; c0 <= c0max; c0++)    for (c1 = c1min; c1 <= c1max; c1++) {      histp = & histogram[c0][c1][c2min];      for (c2 = c2min; c2 <= c2max; c2++) {	if ((count = *histp++) != 0) {	  total += count;	  c0total += ((c0 << C0_SHIFT) + ((1<<C0_SHIFT)>>1)) * count;	  c1total += ((c1 << C1_SHIFT) + ((1<<C1_SHIFT)>>1)) * count;	  c2total += ((c2 << C2_SHIFT) + ((1<<C2_SHIFT)>>1)) * count;	}      }    }    cinfo->colormap[0][icolor] = (JSAMPLE) ((c0total + (total>>1)) / total);  cinfo->colormap[1][icolor] = (JSAMPLE) ((c1total + (total>>1)) / total);  cinfo->colormap[2][icolor] = (JSAMPLE) ((c2total + (total>>1)) / total);}LOCAL(void)select_colors (j_decompress_ptr cinfo, int desired_colors)/* Master routine for color selection */{  boxptr boxlist;  int numboxes;  int i;  /* Allocate workspace for box list */  boxlist = (boxptr) (*cinfo->mem->alloc_small)    ((j_common_ptr) cinfo, JPOOL_IMAGE, desired_colors * SIZEOF(box));  /* Initialize one box containing whole space */  numboxes = 1;  boxlist[0].c0min = 0;  boxlist[0].c0max = MAXJSAMPLE >> C0_SHIFT;  boxlist[0].c1min = 0;  boxlist[0].c1max = MAXJSAMPLE >> C1_SHIFT;  boxlist[0].c2min = 0;  boxlist[0].c2max = MAXJSAMPLE >> C2_SHIFT;  /* Shrink it to actually-used volume and set its statistics */  update_box(cinfo, & boxlist[0]);  /* Perform median-cut to produce final box list */  numboxes = median_cut(cinfo, boxlist, numboxes, desired_colors);  /* Compute the representative color for each box, fill colormap */  for (i = 0; i < numboxes; i++)    compute_color(cinfo, & boxlist[i], i);  cinfo->actual_number_of_colors = numboxes;  TRACEMS1(cinfo, 1, JTRC_QUANT_SELECTED, numboxes);}/* * These routines are concerned with the time-critical task of mapping input * colors to the nearest color in the selected colormap. * * We re-use the histogram space as an "inverse color map", essentially a * cache for the results of nearest-color searches.  All colors within a * histogram cell will be mapped to the same colormap entry, namely the one * closest to the cell's center.  This may not be quite the closest entry to * the actual input color, but it's almost as good.  A zero in the cache * indicates we haven't found the nearest color for that cell yet; the array * is cleared to zeroes before starting the mapping pass.  When we find the * nearest color for a cell, its colormap index plus one is recorded in the * cache for future use.  The pass2 scanning routines call fill_inverse_cmap * when they need to use an unfilled entry in the cache. * * Our method of efficiently finding nearest colors is based on the "locally * sorted search" idea described by Heckbert and on the incremental distance * calculation described by Spencer W. Thomas in chapter III.1 of Graphics * Gems II (James Arvo, ed.  Academic Press, 1991).  Thomas points out that * the distances from a given colormap entry to each cell of the histogram can * be computed quickly using an incremental method: the differences between * distances to adjacent cells themselves differ by a constant.  This allows a * fairly fast implementation of the "brute force" approach of computing the * distance from every colormap entry to every histogram cell.  Unfortunately, * it needs a work array to hold the best-distance-so-far for each histogram * cell (because the inner loop has to be over cells, not colormap entries). * The work array elements have to be INT32s, so the work array would need * 256Kb at our recommended precision.  This is not feasible in DOS machines. * * To get around these problems, we apply Thomas' method to compute the * nearest colors for only the cells within a small subbox of the histogram. * The work array need be only as big as the subbox, so the memory usage * problem is solved.  Furthermore, we need not fill subboxes that are never * referenced in pass2; many images use only part of the color gamut, so a * fair amount of work is saved.  An additional advantage of this * approach is that we can apply Heckbert's locality criterion to quickly * eliminate colormap entries that are far away from the subbox; typically * three-fourths of the colormap entries are rejected by Heckbert's criterion, * and we need not compute their distances to individual cells in the subbox. * The speed of this approach is heavily influenced by the subbox size: too * small means too much overhead, too big loses because Heckbert's criterion * can't eliminate as many colormap entries.  Empirically the best subbox * size seems to be about 1/512th of the histogram (1/8th in each direction). * * Thomas' article also describes a refined method which is asymptotically * faster than the brute-force method, but it is also far more complex and * cannot efficiently be applied to small subboxes.  It is therefore not * useful for programs intended to be portable to DOS machines.  On machines * with plenty of memory, filling the whole histogram in one shot with Thomas' * refined method might be faster than the present code --- but then again, * it might not be any faster, and it's certainly more complicated. *//* log2(histogram cells in update box) for each axis; this can be adjusted */#define BOX_C0_LOG  (HIST_C0_BITS-3)#define BOX_C1_LOG  (HIST_C1_BITS-3)#define BOX_C2_LOG  (HIST_C2_BITS-3)#define BOX_C0_ELEMS  (1<<BOX_C0_LOG) /* # of hist cells in update box */#define BOX_C1_ELEMS  (1<<BOX_C1_LOG)#define BOX_C2_ELEMS  (1<<BOX_C2_LOG)#define BOX_C0_SHIFT  (C0_SHIFT + BOX_C0_LOG)#define BOX_C1_SHIFT  (C1_SHIFT + BOX_C1_LOG)#define BOX_C2_SHIFT  (C2_SHIFT + BOX_C2_LOG)/* * The next three routines implement inverse colormap filling.  They could * all be folded into one big routine, but splitting them up this way saves * some stack space (the mindist[] and bestdist[] arrays need not coexist) * and may allow some compilers to produce better code by registerizing more * inner-loop variables. */LOCAL(int)find_nearby_colors (j_decompress_ptr cinfo, int minc0, int minc1, int minc2,		    JSAMPLE colorlist[])/* Locate the colormap entries close enough to an update box to be candidates * for the nearest entry to some cell(s) in the update box.  The update box * is specified by the center coordinates of its first cell.  The number of * candidate colormap entries is returned, and their colormap indexes are * placed in colorlist[]. * This routine uses Heckbert's "locally sorted search" criterion to select * the colors that need further consideration. */{

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