📄 国家计算机二级考试程序修改与设计(2).htm
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<P align=center><FONT color=#0000ff
size=3><B>国家计算机二级考试程序修改与设计(2)</B></FONT><BR></P>
<P><FONT
color=#ff0000>二级C程序修改2<BR></FONT><BR>===========================================<BR>试题说明
:
<BR>===========================================<BR>给定程序MODI1.C中函数
fun 的功能是：将未在字符串s中出
<BR>现而在字符串t中出现的字符形成一个新的字符串放在u中，u中字
<BR>符按原字符串中字符顺序排列，不去掉重复字符。 <BR>例如，当s = "ABCDE"，t =
"BDFGG"时， <BR>u中的字符串为"FGG"。
<BR>请改正函数fun中的错误，使它能得出正确的结果。注意：不
<BR>要改动main函数，不得增行或删行，也不得更改程序的结构！
<BR>===========================================<BR><B>程序
:
</B><BR>===========================================<BR><FONT
color=#009900>#include <BR>#include <BR>#include
</FONT></P>
<P><FONT color=#009900>void fun (char *s, char *t,
char *u) <BR>{ int i, j, sl, tl; <BR>sl =
strlen(s); tl = strlen(t);
<BR>/************found************/ <BR>for (i=0;
i/************found************/ <BR>{ for (j=0; j
if (t[i] == s[j]) break; <BR>if (j=sl) *u++ =
t[i]; <BR>} <BR>/************found************/
<BR>u = '\0'; <BR>} </FONT></P>
<P><FONT color=#009900>main() <BR>{ char s[100],
t[100], u[100]; <BR>clrscr(); <BR>printf("\nPlease
enter string s:"); scanf("%s", s);
<BR>printf("\nPlease enter string t:");
scanf("%s", t); <BR>fun(s, t, u); <BR>printf("The
result is: %s\n", u); <BR>}
</FONT><BR>===========================================<BR>所需数据
:
<BR>===========================================<BR><FONT
color=#009900>#3 <BR>@1 001006 <BR>for (i=0; ifor
(i=0; ifor (i=0; ifor (i=0; ifor (i=0; ifor (i=0;
i@2 001006 <BR>{for (j=0; j{for (j=0; j{for (j=0;
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