modrc4.bas

文件的加密解密实现

Attribute VB_Name = "RC4"
'found on PSC (dunno who wrote it)

Public Function cRC4(inp As String, key As String) As String
On Error Resume Next

Dim S(0 To 255) As Byte, K(0 To 255) As Byte, i As Long
Dim j As Long, temp As Byte, Y As Byte, t As Long, x As Long
Dim Outp As String

For i = 0 To 255
S(i) = i
Next

j = 1
For i = 0 To 255
If j > Len(key) Then j = 1
K(i) = Asc(Mid(key, j, 1))
j = j + 1
Next i

j = 0
For i = 0 To 255
j = (j + S(i) + K(i)) Mod 256
temp = S(i)
S(i) = S(j)
S(j) = temp
Next i

i = 0
j = 0
For x = 1 To Len(inp)
i = (i + 1) Mod 256
j = (j + S(i)) Mod 256
temp = S(i)
S(i) = S(j)
S(j) = temp
t = (S(i) + (S(j) Mod 256)) Mod 256
Y = S(t)
    
Outp = Outp & Chr(Asc(Mid(inp, x, 1)) Xor Y)
Next
cRC4 = Outp

End Function