计算天数的程序.txt
来自「计算天数的程序,c语言开发」· 文本 代码 · 共 37 行
TXT
37 行
计算天数的程序
#include<stdio.h>
static int day_tab[2][13]={
{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}
};
main()
{int year,month,day;
int year_day;
int leap;
char str[4];
leap=(year%4==0&&year%100!=0)||(year%400==0);
printf(" 请输入日期:[1900--2050]\n ");
for(;;)
{printf(" year=");scanf("%d",&year);
printf(" month=");scanf("%d",&month);
printf(" day=");scanf("%d",&day);
year_day=day_of_year(year,month,day);
if(year<1900||year>2050||month<1||month>12
||day<1||day>day_tab[leap][month])
printf("无效日期!\n");
else
printf("%d年%d月%d日是该年的第%d天\n",year,month,day,year_day);
printf("如果想结束程序请输入end");
gets(str);
if(strcmp(str,"end")==0) break;}
}
day_of_year(year,month,day)
int year,month,day;
{int i,leap;
leap=(year%4==0&&year%100!=0)||(year%400==0);
for(i=1;i<month;i++)
day+=day_tab[leap][i];
return(day);
}
使用exit();在输入end之后.
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