ctime2l.c

Dos6.0

/* routines for converting from ASCII time to long int */
#include <stdio.h>
#include <time.h>

/*  Intended to be the "inverse" of the asctime function of the C library
 *
 *  ctime2l  - takes ascii string in the format returned by ctime
 *	       representing local time and returns a long that is the
 *	       elapsed seconds since 00:00:00 Jan 1, 1970 Greenwich Mean Time
 *  ctime2tm - takes ascii string in the format returned by ctime and
 *	       fills a struct tm
 *  date2l   - takes a date representing local time and returns a long that
 *	       is the elapsed seconds since 00:00:00 Jan 1, 1970 Greenwich Mean Time
 *
 *  Modifications:
 *
 *	08-Sep-1986 mz	Extend time formats accepted to include:
 *	    day mon dd hh:mm:ss yyyy
 *	    mm/dd/yy			(presume 00:00:00)
 *	    hh:mm:ss			(presume hh:mm:ss today)
 *	    hh:mm			(presume hh:mm:00 today)
 *	    +hh:mm:ss			(hh:mm:ss from now)
 *	    +hh:mm			(hh:mm from now)
 *	    +hh 			(hh from now)
 *	    yesterday			(at midnight)
 *	    tomorrow			(at midnight)
 *	    now
 */

#include <string.h>

static int dayinmon[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
static char *strMon[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul",
    "Aug", "Sep", "Oct", "Nov", "Dec"};
static char *strDay[7] =  {"Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"};
static struct tm tb;

// extern long timezone;
// extern int daylight;
extern int _days[];

static time_t _dtoxtime(int, int, int, int, int, int);
static istr(char *, char **, int);
static yday(int, int, int);
static leapyear(int);
struct tm *ctime2tm(char *);
long date2l(int, int, int, int, int, int);

/****************************************************************************/
/* start of copy of code in C lib					    */
/****************************************************************************/

#define DaySec	(24*60*60L)
#define YearSec (365*DaySec)
#define DecSec	315532800L	/* secs in 1970-1979 */
#define Day1	4		/* Jan. 1, 1970 was a Thursday */
#define Day180	2		/* Jan. 1, 1980 was a Tuesday */

#ifdef DANL_OLD_AND_BROKEN

/*
 *  _isindst - Tells whether Xenix-type time value falls under DST
 *
 *  This is the rule:  a time is in DST iff it is on or after 0200:00 on
 *  the last Sunday in April and before 0100:00 on the last Sunday in
 *  October.
 *
 *  ENTRY   tb	- 'time' structure holding broken-down time value
 *
 *  RETURN  1 if time represented is in DST, else 0
 */

static _isindst(tb)
struct tm *tb;
{
    int mdays;
    int yr;
    int lastsun;

/* If the month is before April or after October, then we know immediately
 * it can't be DST. */

	if (tb->tm_mon < 3 || tb->tm_mon > 9)
		return(0);

/* If the month is after April and before October then we know immediately
 * it must be DST. */

	if (tb->tm_mon > 3 && tb->tm_mon < 9)
		return(1);
	/*
	 * Now for the hard part.  Month is April or October; see if date
	 * falls between appropriate Sundays.
	 */

/* The objective si to determine if the day is on or after 2:00 am on the
 * last Sunday in April, or before 1:00 am on the last Sunday in October.
 * We know the year-day( 0 .. 365 ) of the current time structure. We must
 * determine the year-day of the last Sunday itn this month, April or October,
 * and then do the comparison.
 * To determine the year-day of the last Sunday, we do the following:
 *	  1. Get the year-day of the 1st day of the month after the current
 *	     month: May or November.
 *	  2. Determine the week-day number of #1, which is defined as 0 = Sun,
 *	     1 = Mon, ... 6 = Sat
 *	  3. Subtract #2 from #1
 */

	yr = tb->tm_year + 1900;			/* To see if this is a leap-year */

/* First we get #1. The year-days for each month are stored in _days[]
 * they're all off by -1 */

	mdays = 1 + _days[tb->tm_mon+1];

/* if this is a leap-year, add an extra day */
	if (!(yr % 4) && ((yr % 100) || !(yr % 400)))
		mdays++;


/* mdays now has #1 */

	yr = tb->tm_year - 70;

/* Now get #2.	We know the week-day number of the beginning of the epoch,
 * Jan. 1, 1970, which is defined as the constant Day1.  We then add the
 * number of days that have passed from Day1 to the day of #2
 *	mdays + 365 * yr
 * correct for the leap years which intervened
 *	+ (yr + 1)/ 4
 * and take the result mod 7. This is #2, which we then subtract from
 * #1, mdays:
 */

	lastsun = mdays - ((mdays + 365*yr + ((yr+1)/4) + Day1) % 7);

/* Now we know 1 and 3; we're golden: */

	if (tb->tm_mon==3)
		return(tb->tm_yday > lastsun || (tb->tm_yday == lastsun && tb->tm_hour >= 2));
	else
		return(tb->tm_yday < lastsun || (tb->tm_yday == lastsun && tb->tm_hour < 1));
}

#else

/*
 *  _isindst - Tells whether Xenix-type time value falls under DST
 *
 *  This is the rule for years before 1987:
 *  a time is in DST iff it is on or after 02:00:00 on the last Sunday
 *  in April and before 01:00:00 on the last Sunday in October.
 *
 *  This is the rule for years starting with 1987:
 *  a time is in DST iff it is on or after 02:00:00 on the first Sunday
 *  in April and before 01:00:00 on the last Sunday in October.
 *
 *  ENTRY   tb  - 'time' structure holding broken-down time value
 *
 *  RETURN  1 if time represented is in DST, else 0
 */

static int _isindst(register struct tm *tb)
{
    int mdays;
    register int yr;
    int lastsun;

    /* If the month is before April or after October, then we know immediately
     * it can't be DST. */

    if (tb->tm_mon < 3 || tb->tm_mon > 9)
        return(0);

    /* If the month is after April and before October then we know immediately
     * it must be DST. */

    if (tb->tm_mon > 3 && tb->tm_mon < 9)
        return(1);
    /*
     * Now for the hard part.  Month is April or October; see if date
     * falls between appropriate Sundays.
     */

    /*
     * The objective for years before 1987 (after 1986) is to determine
     * if the day is on or after 2:00 am on the last (first) Sunday in April,
     * or before 1:00 am on the last Sunday in October.
     *
     * We know the year-day (0..365) of the current time structure. We must
     * determine the year-day of the last (first) Sunday in this month,
     * April or October, and then do the comparison.
     *
     * To determine the year-day of the last Sunday, we do the following:
     *        1. Get the year-day of the last day of the current month (Apr or Oct)
     *        2. Determine the week-day number of #1,
     *      which is defined as 0 = Sun, 1 = Mon, ... 6 = Sat
     *        3. Subtract #2 from #1
     *
     * To determine the year-day of the first Sunday, we do the following:
     *        1. Get the year-day of the 7th day of the current month (April)
     *        2. Determine the week-day number of #1,
     *      which is defined as 0 = Sun, 1 = Mon, ... 6 = Sat
     *        3. Subtract #2 from #1
     */

    yr = tb->tm_year + 1900;    /* To see if this is a leap-year */

    /* First we get #1. The year-days for each month are stored in _days[]
     * they're all off by -1 */

    if (yr > 1986 && tb->tm_mon == 3)
        mdays = 7 + _days[tb->tm_mon];
    else
        mdays = _days[tb->tm_mon+1];

    /* if this is a leap-year, add an extra day */
    if (!(yr & 3))
        mdays++;

    /* mdays now has #1 */

    yr = tb->tm_year - 70;

    /* Now get #2.  We know the week-day number of the beginning of the epoch,
     * Jan. 1, 1970, which is defined as the constant Day1.  We then add the
     * number of days that have passed from Day1 to the day of #2
     *      mdays + 365 * yr
     * correct for the leap years which intervened
     *      + (yr + 1)/ 4
     * and take the result mod 7, except that 0 must be mapped to 7.
     * This is #2, which we then subtract from #1, mdays
     */

    lastsun = mdays - ((mdays + 365*yr + ((yr+1)/4) + Day1) % 7);

    /* Now we know 1 and 3; we're golden: */

    return (tb->tm_mon==3
        ? (tb->tm_yday > lastsun ||
        (tb->tm_yday == lastsun && tb->tm_hour >= 2))
        : (tb->tm_yday < lastsun ||
        (tb->tm_yday == lastsun && tb->tm_hour < 1)));
}

#endif

static time_t _dtoxtime(yr, mo, dy, hr, mn, sc)
int yr;
int mo, dy, hr, mn, sc;
{
    int mdays;
    long scount;

    scount = ((yr+3)/4)*(long)DaySec;

    /* This is no good beyond the year 2099 */

    mdays = _days[mo-1];
    if (!(yr % 4) && (mo > 2))
	mdays++;
    scount += (yr*365 + dy + mdays)*(long)DaySec + (long)hr*3600L + mn*60L +
		sc + (long)DecSec;
    tb.tm_yday = mdays + dy;
    tzset();
    scount += timezone;
    tb.tm_year = yr + 80;
    tb.tm_mon = mo - 1;
    tb.tm_hour = hr;
    if (daylight && _isindst(&tb))
	scount -= 3600L;
    return(scount);
}


/****************************************************************************/
/* end of copy of code in C lib 					    */
/****************************************************************************/







long date2l(year, month, day, hour, min, sec)
int year, month, day, hour, min, sec;
{
    /* month is (1..12) */
    return _dtoxtime (year - 1980, month, day, hour, min, sec);
}

struct tm *ctime2tm(p)
char *p;
{
    char day[4], mon[4];
    int date, year, hour, min, sec, month;
    long now;

    if (sscanf (p, " %3s %3s %2d %2d:%2d:%2d %4d ",
		   day, mon, &date, &hour, &min, &sec, &year) == 7) {
	tzset();
	tb.tm_sec = sec;
	tb.tm_min = min;
	tb.tm_hour = hour;
	tb.tm_mday = date;
	tb.tm_year = year-1900;
	tb.tm_mon  = istr(mon, strMon, 12);
	tb.tm_wday = istr(day, strDay, 7);
	tb.tm_yday = yday(tb.tm_year, tb.tm_mon, tb.tm_mday);
	tb.tm_isdst = (daylight && _isindst(&tb) ? 1 : 0);
	return &tb;
	}

    if (*p == '+' && sscanf (p+1, " %2d:%2d:%2d ", &hour, &min, &sec) == 3) {
	time (&now);
	now += 3600L * hour + 60L * min + sec;
	tb = *localtime (&now);
	return &tb;
	}
    if (*p == '+' && sscanf (p+1, " %2d:%2d ", &hour, &min) == 2) {
	time (&now);
	now += 3600L * hour + 60L * min;
	tb = *localtime (&now);
	return &tb;
	}
    if (*p == '+' && sscanf (p+1, " %2d ", &hour) == 1) {
	time (&now);
	now += 3600L * hour;
	tb = *localtime (&now);
	return &tb;
	}

    if (sscanf (p, " %2d:%2d:%2d ", &hour, &min, &sec) == 3) {
	time (&now);
	tb = *localtime (&now);
	tb.tm_sec = sec;
	tb.tm_min = min;
	tb.tm_hour = hour;
	return &tb;
	}
    if (sscanf (p, " %2d:%2d ", &hour, &min) == 2) {
	time (&now);
	tb = *localtime (&now);
	tb.tm_sec = 0;
	tb.tm_min = min;
	tb.tm_hour = hour;
	return &tb;
	}

    if (sscanf (p, " %2d/%2d/%2d ", &month, &date, &year) == 3) {
	if (year < 70)
	    year += 2000;
	if (year < 100)
	    year += 1900;
	tzset();
	now = _dtoxtime (year - 1980, month, date, 0, 0, 0);
	tb = *localtime (&now);
	return &tb;
	}

    if (!strcmp (p, "yesterday")) {
	time (&now);
	now -= 24 * 3600L;
	tb = *localtime (&now);
	tb.tm_sec = 0;
	tb.tm_min = 0;
	tb.tm_hour = 0;
	return &tb;
	}
    if (!strcmp (p, "now")) {
	time (&now);
	tb = *localtime (&now);
	return &tb;
	}
    if (!strcmp (p, "tomorrow")) {
	time (&now);
	now += 24 * 3600L;
	tb = *localtime (&now);
	tb.tm_sec = 0;
	tb.tm_min = 0;
	tb.tm_hour = 0;
	return &tb;
	}

    return NULL;
}

long ctime2l(p)
char *p;
{
    if (ctime2tm(p) == NULL)
	return -1L;
    return date2l (tb.tm_year +1900, tb.tm_mon + 1, tb.tm_mday, tb.tm_hour,
	tb.tm_min, tb.tm_sec);
}


static leapyear(i)
int i;
{
    return (!i%4 && i%100);
}


static yday(year, mon, day)
int year, mon, day;
{
    int i, j;

    /* year = 1986 is 86 */
    /* mon (0..11)	 */
    j = day -1;
    for (i=0; i < mon; i++)
	j += dayinmon[i];
    if (mon > 2 && leapyear(year))
	j++;
    return j;
}

static istr(p, q, len)
char *p;
char **q;
int len;
{
    int i;

    for (i=0; i < len; i++)
	if (strcmpi(p, *q++)== 0)
	    break;
    return i;
}