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📄 web216colorsfilter.java

📁 用JGraph编的软件
💻 JAVA
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/* * @(#)Web216ColorsFilter.java   05/16/2000 * * Copyright (c) 2000-2001 Emmanuel PUYBARET / eTeks <info@eteks.com>. All Rights Reserved. * * This program is free software; you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation; either version 2 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program; if not, write to the Free Software * Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA * * Visit eTeks web site for up-to-date versions of this file and other * Java tools and tutorials : http://www.eteks.com/ */package com.eteks.filter;import java.awt.image.RGBImageFilter;/** * This image filter transforms the color of each pixel of an image, using * a fixed 216 colors palette. No special dithering is performed.<br> * Each Red, Green, Blue component of the 216 colors resulting palette take a value * among the 6 values of the following set : (0x00, 0x33, 0x66, 0x99, OxCC, OxFF). * 6 power 3 makes 216 total possible combinations. * * @version   1.1 * @author    Emmanuel Puybaret * @since     PJA1.0 */public class Web216ColorsFilter extends RGBImageFilter{  {    canFilterIndexColorModel = true;  }  /**   * <code>RGBImageFilter</code> method implementation.   */  public int filterRGB (int x, int y, int rgb)  {    int alpha = rgb & 0xFF000000;    int red   = (rgb & 0xFF0000) >>> 16;    int green = (rgb & 0x00FF00) >>> 8;    int blue  = (rgb & 0x0000FF);    // A very poor filtering that just searchs the Web 216 closest color    red   = red / 0x33 * 0x33 + (red % 0x33 > 0x16 ? 0x33 : 0);    green = green / 0x33 * 0x33 + (green % 0x33 > 0x16 ? 0x33 : 0);    blue  = blue / 0x33 * 0x33 + (blue % 0x33 > 0x16 ? 0x33 : 0);    return alpha | (red << 16) | (green << 8) | blue;  }}

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