📄 get_elements.xtp
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<title section="Resin : XML Tutorial : ">Scanning Elements</title><p/>This Example extracts and print the "b" node in the following XML.<example title="Input XML"><top> <a/> <b> <b1/> <b2/> </b> <c/></top></example><p/>In XML, the document contains a single top element. We'll just extractthat and store it.<p/>Each DOM node has a <var/name/> and a <var/value/> retrieved using<var/getNodeName()/> and <var/getNodeValue()/>. For an Element, the<var/name/> is the tag name and the <var/value/> is null.<p/>Traversing nodes uses a combination of:<ul><li><var/getFirstChild()/><li><var/getLastChild()/><li><var/getNextSibling()/><li><var/getPreviousSibling()/><li><var/getParentNode()/></ul>Since those return a <var/Node/>, you'll often need to cast the results tothe correct type. Remember, that the child nodes also includes <var/Text/>nodes, including whitespace-only text nodes. You can't assume that anychild is an Element, So you'll always need to test the node name orthe node type.<p/>The following pattern is a common method for findinga node as the child.<example title="Finding Elements with the DOM">import java.io.*;import javax.xml.parsers.*;import org.w3c.dom.*;import com.caucho.xml.*;...// Create a new parser using the JAXP API (javax.xml.parsers)DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();DocumentBuilder builder = factory.newDocumentBuilder();// Create a new documentDocument doc = builder.parse("test.xml");// Get the top elementElement top = doc.getDocumentElement();// Find the B elementNode ptr;for (ptr = top.getFirstChild(); ptr != null && ! ptr.getNodeName().equals("b"); ptr = ptr.getNextSibling()) {}</example>
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