📄 rfc963.txt
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is the last fragment, since the routine reassembly, which actually sets these bits, has not yet been called for this fragment. This statement must therefore skip the bits corresponding to the incoming fragment. In specifying the range to be tested, allowance must be made for whether these bits fall at the beginning of the bit map or in the middle (the case where they fall at the end has already been tested). The statement must therefore be changed to read if from_SNP.dtgm.fragment_offset = 0 then if (all reassembly map from from_SNP.dtgm.fragment_offset + ((from_SNP.dtgm.total_length - from_SNP.dtgm.header_length * 4) + 7) / 8 to ((state_vector.total_data_length + 7) / 8 - 1) is set) then return YES; else return NO; end if; else if (all reassembly map from 0 to (from_SNP.dtgm.fragment_offset - 1) is set) and (all reassembly map from from_SNP.dtgm.fragment_offset + ((from_SNP.dtgm.total_length - from_SNP.dtgm.header_length * 4) + 7) / 8 to ((state_vector.total_data_length + 7) / 8 - 1) is set) then return YES; else return NO; end if; end if;Sidhu [Page 7]RFC 963 November 1985Some Problems with MIL-STD IP Note that here again it is necessary to subtract 1 from the upper bound. Problem 4: Errors in fragment_and_send The action procedure fragment_and_send [MILS83a, sec 9.4.6.3.7] is used to break up datagrams that are too large to be sent through the subnetwork as a single packet. The specification requires [MILS83a sec 9.2.2, sec 9.4.6.3.7] each fragment, except possibly the "tail" fragment, to contain a whole number of 8-octet groups (called "blocks"); moreover, each fragment must begin at a block boundary. In the algorithm set forth in fragment_and_send, all fragments except the tail fragment are set to the same size; the procedure begins by calculating this size. This is done by the following statement: data_per_fragment := maximum subnet transmission unit - (20 + number of bytes of option data); Besides the failure to allow for header padding, which is discussed in the next section, this statement makes the serious error of not assuring that the result is an integral multiple of the block size, i.e., a multiple of eight octets. The consequence of this would be that as many as seven octets per fragment would never be sent at all. To correct this problem, and to allow for header padding, this statement must be changed to data_per_fragment := (maximum subnet transmission unit - (((20 + number of bytes of option data)+3)/4*4)/8*8; Another problem in this procedure is the failure to provide for the case in which the length of the data is an exact multiple of eight. The procedure contains the statements number_of fragments := (from_ULP.length + (data_per_fragment - 1)) / data_per_fragment; data_in_last_frag := from_ULP.length modulo data_per_fragment; (Note that in our terminology we would rename data_in_last_frag as data_in_tail_frag; notice, also, that the proper spelling of the Ada operator is mod [ADA83, sec 4.5.5].) If data_in_last_frag is zero, some serious difficulties arise. One result might be that the datagram will be broken into one moreSidhu [Page 8]RFC 963 November 1985Some Problems with MIL-STD IP fragment than necessary, with the tail fragment containing no data bytes. The assignment of data into the tail fragment will succeed even though it will now take the form output_data [i..i-1] := input_data [j..j-1]; because Ada makes provision for so-called "null slices" [ADA83, sec 4.1.2] and will treat this assignment as a no-op [ADA83, sec 5.2.1]. This does, however, cause the transmission of an unnecessary packet, and also creates difficulties for the reassembly procedure, which must now be prepared to handle empty packets, for which not even one bit of the reassembly map should be set. Moreover, as the procedure is now written, even this will not occur. This is because the calculation of the number of fragments is incorrect. A numerical example will clarify this point. Suppose that the total datagram length is 16 bytes and that the number of bytes per fragment is to be 8. Then the above statements will compute number_of_fragments = (16 + 7)/8 = 2 and data_in_last_frag = 16 mod 8 = 0. The result of the inconsistency between number_of_fragments and data_in_last_frag will be that instead of sending three fragments, of lengths 8, 8, and 0, the procedure will send only two fragments, of lengths 8 and 0; the last eight octets will never be sent. To avoid these difficulties, the specification should add the following statement, immediately after computing data_in_last_frag: if data_in_last_frag = 0 then data_in_last_frag := data_per_fragment; end if; This procedure also contains several minor errors. In addition to failures to account for packet header padding, which are enumerated in the next section, there is a failure to convert the header length from words (four octets) to octets in one statement. This statement, which calculates the total length of the non-tail fragments, is to_SNP.dtgm.total_length := to_SNP.dtgm.header_length + data_per_fragment;Sidhu [Page 9]RFC 963 November 1985Some Problems with MIL-STD IP Since header length is expressed in units of words, this statement should read to_SNP.dtgm.total_length := to_SNP.dtgm.header_length * 4 + data_per_fragment; This is apparently no more than a misprint, since the corresponding calculation for the tail fragment is done correctly. Problem 5: Errors in reassembly The action procedure reassembly [MILS83a, sec 9.4.6.3.9], which is referred to as reassemble elsewhere in the specification [MILS83a, sec 9.4.6.1.2, sec 9.4.6.1.3], inserts an incoming fragment into a datagram being reassembled. This procedure contains several relatively minor errors. In two places in this procedure, a range is written to contain one more member than it ought to have. In the first, data from the fragment is to be inserted into the datagram being reassembled: state_vector.data [from_SNP.dtgm.fragment_offset*8 .. from_SNP.dtgm.fragment_offset*8 + data_in_frag] := from_SNP.dtgm.data [0..data_in_frag-1]; In this statement, the slice on the left contains one more byte than the slice on the right. This will cause a run-time exception to be raised [ADA83, sec 5.2.1]. The statement should read state_vector.data [from_SNP.dtgm.fragment_offset*8 .. from_SNP.dtgm.fragment_offset*8 + data_in_frag - 1] := from_SNP.dtgm.data [0..data_in_frag-1]; A similar problem occurs in the computation of the range of bits in the reassembly map that corresponds to the incoming fragment. This statement begins for j in (from_SNP.dtgm.fragment_offset) .. ((from_SNP.dtgm.fragment_offset + data_in_frag + 7)/8) loop Not only are the parentheses in this statement located incorrectly (because the function f(x) = (x + 7) / 8 should be executed only on the argument data_in_frag), but also this range contains one extra member. The statement should readSidhu [Page 10]RFC 963 November 1985Some Problems with MIL-STD IP for j in (from_SNP.dtgm.fragment_offset) .. (from_SNP.dtgm.fragment_offset + (data_in_frag + 7)/8) - 1 loop Note that if the statement is corrected in this manner it will also handle the case of a zero-length fragment, mentioned above, since the loop will not be executed even once [ADA83, sS 5.5]. Another minor problem occurs when this procedure attempts to save the header of the leading fragment. The relevant statement is state_vector.header := from_SNP.dtgm; This statement attempts to transfer the entire incoming fragment into a record that is big enough to contain only the header. The result, in Ada, is not truncation, but a run-time exception [ADA83, sec 5.2]. The correction should be something like state_vector.header := from_SNP.dtgm.header; This correction cannot be made without also defining the header portion of the datagram as a subrecord in [MILS83a, sec 9.4.4.6]; such a definition would also necessitate changing many other statements. For example, from_SNP.dtgm.fragment_offset would now have to be written as from_SNP.dtgm.header.fragment_offset. Another possible solution is to write the above statement as a series of assignments for each field in the header, in the following fashion: state_vector.header.version := from_SNP.dtgm.version; state_vector.header.header_length := from_SNP.dtgm.header_length; state_vector.header.type_of_service := from_SNP.dtgm.type_of_service; -- etc. Note also that this procedure will fail if an incoming fragment, other than the tail fragment, does not contain a multiple of eight characters. Implementors must be careful to check for this in the decision function SNP_params_valid [MILS83a, sec 9.4.6.2.7].Sidhu [Page 11]RFC 963 November 1985Some Problems with MIL-STD IP Problem 6: Incorrect Data Length for Fragmented Datagrams The procedure reassembled_delivery [MILS83a, sec 9.4.6.3.10] does not deliver the proper data length to the upper-level protocol. This is because the assignment is to_ULP.length := state_vector.header.total_length - state_vector.header.header_length * 4; The fields in state_vector.header have been filled in by the reassembly procedure, discussed above, by copying the header of the leading fragment. The field total_length in this fragment, however, refers only to this particular fragment, and not to the entire datagram (this is not entirely clear from it definition in [MILS83a, sec 9.3.4], but the fragment_and_send procedure [MILS83a, sec 9.4.6.3.7] insures that this is the case). The length of the entire datagram can only be computed from the length and offset of the tail fragment. This computation is actually done in the reassembly procedure [MILS83a, sec 9.4.6.3.9], and the result saved in state_vector.total_data_length (see above). It is impossible, however, for reassembly to fill in state_vector.header.total_length at this time, because state_vector.header.header_length is filled in from the lead fragment, which may not yet have been received. Therefore, reassembled_delivery must replace the above statement with to_ULP.length := state_vector.total_data_length; The consequence of leaving this error uncorrected is that the upper-level protocol will be informed only of the delivery of as many octets as there are in the lead fragment.5. Implementation Difficulties of MIL Standard IP In addition to the problems discussed above, there are several features of the MIL standard IP specification [MILS83a] which lead to difficulties for the implementor. These difficulties, while not actually errors in the specification, take the form of assumptions which are not explicitly stated, but of which implementors must be aware.Sidhu [Page 12]RFC 963 November 1985Some Problems with MIL-STD IP 5.1 Header Padding In several places, the specification makes a computation of the length of a packet header without explicitly allowing for padding. The padding is needed because the specification requires [MILS83a, sec 9.3.14] that each header end on a 32-bit boundary. One place this problem arises is in the need_to_frag decision function [MILS83a, sec 9.4.6.2.5]. This function is used to determine whether fragmentation is required for an outgoing datagram. It consists of the single statement if ((from_ULP.length + (number of bytes of option data) + 20) > maximum transmission unit of the local subnetwork then return YES else return NO; end if; (A minor syntax error results from not terminating the first return statement with a semicolon [ADA83, sec 5.1, sec 5.3, sec 5.9].) In order to allow for padding, the expression for the length of the outgoing datagram should be (((from_ULP.length + (number of bytes of option data) + 20) + 3)/4 * 4) Another place that this problem arises is in the action procedure build_and_send [MILS83a, sec 9.4.6.3.2], which prepares unfragmented datagrams for transmission. To compute the header field header_length, which is expressed in words, i.e., units of four octets [MILS83a, sec 9.3.2], this procedure contains the statement to_SNP.dtgm.header_length := 5 +
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