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style="FONT-SIZE: 9pt; COLOR: black; FONT-FAMILY: Arial">i=6</SPAN></P></TD>
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style="FONT-SIZE: 9pt; COLOR: black; FONT-FAMILY: Arial">i=7</SPAN></P></TD>
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lang=EN-US
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lang=EN-US
style="FONT-SIZE: 9pt; COLOR: yellow; FONT-FAMILY: Arial">6</SPAN></P></TD>
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lang=EN-US
style="FONT-SIZE: 9pt; COLOR: yellow; FONT-FAMILY: Arial">8</SPAN></P></TD>
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width="13%">
<P class=MsoNormal style="TEXT-ALIGN: center" align=center><SPAN
lang=EN-US
style="FONT-SIZE: 9pt; COLOR: yellow; FONT-FAMILY: Arial">9</SPAN></P></TD></TR></TBODY></TABLE>
<P class=MsoNormal style="TEXT-ALIGN: left" align=left><SPAN lang=EN-US
style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><BR><BR></SPAN><SPAN
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: 宋体">程序如下:</SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"> </SPAN></P>
<P class=MsoNormal style="TEXT-ALIGN: left" align=left><SPAN
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: 宋体">直接插入排序</SPAN><SPAN
lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">:</SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><BR>void docr(float
*in,int count)<BR>{<BR> int i,j,x;<BR> float temp;<BR>
for(i=1;i<count;i++)<BR> {<BR>
for(x=0;x<i;x++)<BR>
{<BR>
if((*(in+i))<=(*(in+x)))<BR>
break;<BR> }<BR>
temp=*(in+i);<BR>
for(j=i;j>x;j--)<BR>
{<BR>
*(in+j)=*(in+j-1);<BR> }<BR>
*(in+x)=temp;<BR> }<BR>}<BR></SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">最小比较次数:</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">n </SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"> </SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">最大比较次数:</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">n*n/2</SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><BR></SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">最小移动次数:</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">2n</SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"> </SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">最大移动次数:</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">n*n/2</SPAN><SPAN
lang=EN-US
style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><BR><BR></SPAN><SPAN
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: 宋体">二分法插入排序</SPAN><SPAN
lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">:(</SPAN><SPAN
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: 宋体">比较部分用二分法</SPAN><SPAN
lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">)</SPAN><SPAN
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: 宋体">常用算法</SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><BR>void docr(float
*in,int count)<BR>{<BR>int i,j,x;<BR>int l,r,m;<BR>float
temp;<BR>for(i=1;i<count;i++)<BR>
{<BR> l=0;<BR>
r=i-1;<BR> temp=*(in+i);<BR>
while(l<=r)<BR>
{<BR> <BR>
m=(int)((l+r)/2);<BR>
if(temp<=(*(in+m)))<BR>
{<BR>
r=m-1;<BR>
}<BR>
else<BR>
{<BR>
l=m+1;<BR>
}<BR> }<BR>
for(j=i;j>l;j--)<BR>
{<BR>
*(in+j)=*(in+j-1);<BR> }<BR>
*(in+l)=temp;<BR> }<BR>} <BR></SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">移动次数</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">: <SPAN
style="COLOR: red">n*log2(n)</SPAN><BR></SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">最小移动次数:</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">2n</SPAN><SPAN
lang=EN-US style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"> </SPAN><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体">最大移动次数:</SPAN><SPAN lang=EN-US
style="FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">n*n/2</SPAN></P></TD></TR></TBODY></TABLE></DIV>
<P class=MsoNormal><SPAN lang=EN-US></SPAN> </P></DIV></BODY></HTML>
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