📄 ch1.h
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/************************************************
Expect bugs!
Please use and enjoy, and let me know of any bugs/mods/improvements
that you have found/implemented and I will fix/incorporate them into
this file. Thank Mr. Xushiliang once again.
hujinshan@2002.11.3
Airforce Engineering University
************************************************/
/***** #include "CH1.h" 线性代数方程组的求解 *****/
#ifndef CH1_H_
#define CH1_H_
#include "stdlib.h"
#include "math.h"
#include "stdio.h"
#include "CH2.h"
//*******************************************************************
int agaus(double a[],double b[],int n);//全选主元高斯消去法
int agjdn(double a[],double b[],int n,int m);//全选主元高斯约当消去法
int acgas(double ar[],double ai[],int n,double br[],double bi[]);//复系数方程组全选主元高斯消去法
int acjdn(double ar[],double ai[],double br[],double bi[],int n,int m);//复系数方程组全选主元高斯约当消去法
int atrde(double b[],int n,int m,double d[]);//三对角线方程的追赶法
int aband(double b[],double d[],int n,int l,int il,int m);//一般带型方程的求解--**例子程序有溢出,解的值就为零!**
int aldle(double a[],int n,int m,double c[]);//求解对称方程组的分解法
int achol(double a[],int n,int m,double d[]);//求解对称正定方程组的平方根法Cholesky
int aggje(double a[],int n,double b[]);//求解大型稀疏方程组的全选主元高斯约当消去法
int atlvs(double t[],int n,double b[],double x[]);//求解托伯利兹方程组的列文方法
int agsdl(double a[],double b[],int n,double x[],double eps);//高斯-赛德尔迭代法
void agrad(double a[],int n,double b[],double eps,double x[]);//求解对称正定方程组的共轭梯度法
int agmqr(double a[],int m,int n,double b[],double q[]);//求解最小二乘问题的豪斯荷尔德变换法
int agmiv(double a[],int m,int n,double b[],double x[],double aa[],double eps,double u[],double v[],int ka);//求解最小二乘问题的广义逆法
int abint(double a[],int n,double b[],double eps,double x[]);//病态方程组的求解
//*******************************************************************
//int agaus(double* a,double* b,int n)
int agaus(double a[],double b[],int n)
{
int *js,l,k,i,j,is,p,q;
double d,t;
js=(int*)malloc(n*sizeof(int));
l=1;
for (k=0;k<=n-2;k++)
{ d=0.0;
for (i=k;i<=n-1;i++)
for (j=k;j<=n-1;j++)
{ t=fabs(a[i*n+j]);
if (t>d) { d=t; js[k]=j; is=i;}
}
if (d+1.0==1.0) l=0;
else
{ if (js[k]!=k)
for (i=0;i<=n-1;i++)
{ p=i*n+k; q=i*n+js[k];
t=a[p]; a[p]=a[q]; a[q]=t;
}
if (is!=k)
{ for (j=k;j<=n-1;j++)
{ p=k*n+j; q=is*n+j;
t=a[p]; a[p]=a[q]; a[q]=t;
}
t=b[k]; b[k]=b[is]; b[is]=t;
}
}
if (l==0)
{ free(js); //printf("fail\n");
return(0);
}
d=a[k*n+k];
for (j=k+1;j<=n-1;j++)
{ p=k*n+j; a[p]=a[p]/d;}
b[k]=b[k]/d;
for (i=k+1;i<=n-1;i++)
{ for (j=k+1;j<=n-1;j++)
{ p=i*n+j;
a[p]=a[p]-a[i*n+k]*a[k*n+j];
}
b[i]=b[i]-a[i*n+k]*b[k];
}
}
d=a[(n-1)*n+n-1];
if (fabs(d)+1.0==1.0)
{ free(js); //printf("fail\n");
return(0);
}
b[n-1]=b[n-1]/d;
for (i=n-2;i>=0;i--)
{ t=0.0;
for (j=i+1;j<=n-1;j++)
t=t+a[i*n+j]*b[j];
b[i]=b[i]-t;
}
js[n-1]=n-1;
for (k=n-1;k>=0;k--)
if (js[k]!=k)
{ t=b[k]; b[k]=b[js[k]]; b[js[k]]=t;}
free(js);
return(1);
}
/////////////////////////////////////////////////////////////////
int agjdn(double a[],double b[],int n,int m)
{ int *js,l,k,i,j,is,p,q;
double d,t;
js=(int*)malloc(n*sizeof(int));
l=1;
for (k=0;k<=n-1;k++)
{ d=0.0;
for (i=k;i<=n-1;i++)
for (j=k;j<=n-1;j++)
{ t=fabs(a[i*n+j]);
if (t>d) { d=t; js[k]=j; is=i;}
}
if (d+1.0==1.0) l=0;
else
{ if (js[k]!=k)
for (i=0;i<=n-1;i++)
{ p=i*n+k; q=i*n+js[k];
t=a[p]; a[p]=a[q]; a[q]=t;
}
if (is!=k)
{ for (j=k;j<=n-1;j++)
{ p=k*n+j; q=is*n+j;
t=a[p]; a[p]=a[q]; a[q]=t;
}
for (j=0;j<=m-1;j++)
{ p=k*m+j; q=is*m+j;
t=b[p]; b[p]=b[q]; b[q]=t;
}
}
}
if (l==0)
{ free(js); //printf("fail\n");
return(0);
}
d=a[k*n+k];
for (j=k+1;j<=n-1;j++)
{ p=k*n+j; a[p]=a[p]/d;}
for (j=0;j<=m-1;j++)
{ p=k*m+j; b[p]=b[p]/d;}
for (j=k+1;j<=n-1;j++)
for (i=0;i<=n-1;i++)
{ p=i*n+j;
if (i!=k)
a[p]=a[p]-a[i*n+k]*a[k*n+j];
}
for (j=0;j<=m-1;j++)
for (i=0;i<=n-1;i++)
{ p=i*m+j;
if (i!=k)
b[p]=b[p]-a[i*n+k]*b[k*m+j];
}
}
for (k=n-1;k>=0;k--)
if (js[k]!=k)
for (j=0;j<=m-1;j++)
{ p=k*m+j; q=js[k]*m+j;
t=b[p]; b[p]=b[q]; b[q]=t;
}
free(js);
return(1);
}
///////////////////////acgas(&ar[0][0],&ai[0][0],4,&br[0],&bi[0])
int acgas(double ar[],double ai[],int n,double br[],double bi[])
{
int *js,l,k,i,j,is,u,v;
double p,q,s,d;
js=(int*)malloc(n*sizeof(int));
for (k=0;k<=n-2;k++)
{ d=0.0;
for (i=k;i<=n-1;i++)
for (j=k;j<=n-1;j++)
{
u=i*n+j;
p=ar[u]*ar[u]+ai[u]*ai[u];
if (p>d) {d=p;js[k]=j;is=i;}
}
if (d+1.0==1.0)
{
free(js); //printf("err**fail\n");
return(0);
}
if (is!=k)
{
for (j=k;j<=n-1;j++)
{
u=k*n+j; v=is*n+j;
p=ar[u]; ar[u]=ar[v]; ar[v]=p;
p=ai[u]; ai[u]=ai[v]; ai[v]=p;
}
p=br[k]; br[k]=br[is]; br[is]=p;
p=bi[k]; bi[k]=bi[is]; bi[is]=p;
}
if (js[k]!=k)
for (i=0;i<=n-1;i++)
{
u=i*n+k; v=i*n+js[k];
p=ar[u]; ar[u]=ar[v]; ar[v]=p;
p=ai[u]; ai[u]=ai[v]; ai[v]=p;
}
v=k*n+k;
for (j=k+1;j<=n-1;j++)
{
u=k*n+j;
p=ar[u]*ar[v]; q=-ai[u]*ai[v];
s=(ar[v]-ai[v])*(ar[u]+ai[u]);
ar[u]=(p-q)/d; ai[u]=(s-p-q)/d;
}
p=br[k]*ar[v]; q=-bi[k]*ai[v];
s=(ar[v]-ai[v])*(br[k]+bi[k]);
br[k]=(p-q)/d; bi[k]=(s-p-q)/d;
for (i=k+1;i<=n-1;i++)
{
u=i*n+k;
for (j=k+1;j<=n-1;j++)
{
v=k*n+j; l=i*n+j;
p=ar[u]*ar[v]; q=ai[u]*ai[v];
s=(ar[u]+ai[u])*(ar[v]+ai[v]);
ar[l]=ar[l]-p+q;
ai[l]=ai[l]-s+p+q;
}
p=ar[u]*br[k]; q=ai[u]*bi[k];
s=(ar[u]+ai[u])*(br[k]+bi[k]);
br[i]=br[i]-p+q; bi[i]=bi[i]-s+p+q;
}
}
u=(n-1)*n+n-1;
d=ar[u]*ar[u]+ai[u]*ai[u];
if (d+1.0==1.0)
{
free(js); //printf("err**fail\n");
return(0);
}
p=ar[u]*br[n-1]; q=-ai[u]*bi[n-1];
s=(ar[u]-ai[u])*(br[n-1]+bi[n-1]);
br[n-1]=(p-q)/d; bi[n-1]=(s-p-q)/d;
for (i=n-2;i>=0;i--)
for (j=i+1;j<=n-1;j++)
{
u=i*n+j;
p=ar[u]*br[j]; q=ai[u]*bi[j];
s=(ar[u]+ai[u])*(br[j]+bi[j]);
br[i]=br[i]-p+q;
bi[i]=bi[i]-s+p+q;
}
js[n-1]=n-1;
for (k=n-1;k>=0;k--)
if (js[k]!=k)
{
p=br[k]; br[k]=br[js[k]]; br[js[k]]=p;
p=bi[k]; bi[k]=bi[js[k]]; bi[js[k]]=p;
}
free(js);
return(1);
}
/////////////if (acjdn(&ar[0][0],&ai[0][0],&br[0][0],&bi[0][0],4,2)!=0)
int acjdn(double ar[],double ai[],double br[],double bi[],int n,int m)
{
int *js,l,k,i,j,is,u,v;
double p,q,s,d;
js=(int*)malloc(n*sizeof(int));
for (k=0;k<=n-1;k++)
{
d=0.0;
for (i=k;i<=n-1;i++)
for (j=k;j<=n-1;j++)
{
u=i*n+j;
p=ar[u]*ar[u]+ai[u]*ai[u];
if (p>d)
{
d=p;js[k]=j;is=i;
}
}
if (d+1.0==1.0)
{
free(js); printf("err**fail\n");
return(0);
}
if (is!=k)
{
for (j=k;j<=n-1;j++)
{
u=k*n+j; v=is*n+j;p=ar[u];
ar[u]=ar[v]; ar[v]=p; p=ai[u];
ai[u]=ai[v]; ai[v]=p;
}
for (j=0;j<=m-1;j++)
{ u=k*m+j; v=is*m+j;
p=br[u]; br[u]=br[v]; br[v]=p;
p=bi[u]; bi[u]=bi[v]; bi[v]=p;
}
}
if (js[k]!=k)
for (i=0;i<=n-1;i++)
{ u=i*n+k; v=i*n+js[k];
p=ar[u]; ar[u]=ar[v]; ar[v]=p;
p=ai[u]; ai[u]=ai[v]; ai[v]=p;
}
v=k*n+k;
for (j=k+1;j<=n-1;j++)
{ u=k*n+j;
p=ar[u]*ar[v]; q=-ai[u]*ai[v];
s=(ar[v]-ai[v])*(ar[u]+ai[u]);
ar[u]=(p-q)/d; ai[u]=(s-p-q)/d;
}
for (j=0;j<=m-1;j++)
{ u=k*m+j;
p=br[u]*ar[v]; q=-bi[u]*ai[v];
s=(ar[v]-ai[v])*(br[u]+bi[u]);
br[u]=(p-q)/d; bi[u]=(s-p-q)/d;
}
for (i=0;i<=n-1;i++)
if (i!=k)
{ u=i*n+k;
for (j=k+1;j<=n-1;j++)
{ v=k*n+j; l=i*n+j;
p=ar[u]*ar[v]; q=ai[u]*ai[v];
s=(ar[u]+ai[u])*(ar[v]+ai[v]);
ar[l]=ar[l]-p+q;
ai[l]=ai[l]-s+p+q;
}
for (j=0;j<=m-1;j++)
{ l=i*m+j; v=k*m+j;
p=ar[u]*br[v]; q=ai[u]*bi[v];
s=(ar[u]+ai[u])*(br[v]+bi[v]);
br[l]=br[l]-p+q; bi[l]=bi[l]-s+p+q;
}
}
}
for (k=n-1;k>=0;k--)
if (js[k]!=k)
for (j=0;j<=m-1;j++)
{ u=k*m+j;v=js[k]*m+j;
p=br[u]; br[u]=br[v]; br[v]=p;
p=bi[u]; bi[u]=bi[v]; bi[v]=p;
}
free(js);
return(1);
}
///////////////////// if (atrde(b,5,13,d)>0)
int atrde(double b[],int n,int m,double d[])
{ int k,j;
double s;
if (m!=(3*n-2))
{ printf("err\n"); return(-2);}
for (k=0;k<=n-2;k++)
{ j=3*k; s=b[j];
if (fabs(s)+1.0==1.0)
{ printf("fail\n"); return(0);}
b[j+1]=b[j+1]/s;
d[k]=d[k]/s;
b[j+3]=b[j+3]-b[j+2]*b[j+1];
d[k+1]=d[k+1]-b[j+2]*d[k];
}
s=b[3*n-3];
if (fabs(s)+1.0==1.0)
{ printf("fail\n"); return(0);}
d[n-1]=d[n-1]/s;
for (k=n-2;k>=0;k--)
d[k]=d[k]-b[3*k+1]*d[k+1];
return(2);
}
/////////////////////////////////////////////////////////////
int aband(double b[],double d[],int n,int l,int il,int m)
{ int ls,k,i,j,is,u,v;
double p,t;
if (il!=(2*l+1))
{ printf("fail\n"); return(-2);}
ls=l;
for (k=0;k<=n-2;k++)
{ p=0.0;
for (i=k;i<=ls;i++)
{ t=fabs(b[i*il]);
if (t>p) {p=t; is=i;}
}
if (p+1.0==1.0)
{ printf("fail\n"); return(0);}
for (j=0;j<=m-1;j++)
{ u=k*m+j; v=is*m+j;
t=d[u]; d[u]=d[v]; d[v]=t;
}
for (j=0;j<=il-1;j++)
{ u=k*il+j; v=is*il+j;
t=b[u]; b[u]=b[v]; b[v]=t;
}
for (j=0;j<=m-1;j++)
{ u=k*m+j; d[u]=d[u]/b[k*il];}
for (j=1;j<=il-1;j++)
{ u=k*il+j; b[u]=b[u]/b[k*il];}
for (i=k+1;i<=ls;i++)
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