经典算法拉丁方阵.cpp

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#include <stdio.h>
void main()
{
	int a[9][9],n,i,j,sum = 0;
	scanf("%d",&n);
	for (i=0; i<n; i++)
	{	
		int k = i;
		for (j=1; j<=n; j++)
		{
			a[i+1][j] = (k % n)+1;
			k ++;
		}
	}
	for (i = 1; i <= n; i++)
	{
		for (j = 1; j <= n; j++)
			printf("%4d",a[i][j]);
		printf("\n");
	}

}