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int i;<br>
s=0;<br>
for(i=1;i<=n;i+=2)<br>
s+=1/(float)i;<br>
return(s);<br>
}<br>
float dcall(fp,n)<br>
float (*fp)();<br>
int n;<br>
{<br>
float s;<br>
s=(*fp)(n);<br>
return(s);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序77】</font><br>
题目:填空练习(指向指针的指针)<br>
1.程序分析: <br>
2.程序源代码:<br>
main()<br>
{ char *s[]={"man","woman","girl","boy","sister"};<br>
char **q;<br>
int k;<br>
for(k=0;k<5;k++)<br>
{ ;/*这里填写什么语句*/<br>
printf("%s\n",*q);<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序78】</font><br>
题目:找到年龄最大的人,并输出。请找出程序中有什么问题。<br>
1.程序分析:<br>
2.程序源代码:<br>
#define N 4<br>
#include "stdio.h"<br>
static struct man<br>
{ char name[20];<br>
int age;<br>
} person[N]={"li",18,"wang",19,"zhang",20,"sun",22};<br>
main()<br>
{struct man *q,*p;<br>
int i,m=0;<br>
p=person;<br>
for (i=0;i<N;i++)<br>
{if(m<p->age)<br>
q=p++;<br>
m=q->age;}<br>
printf("%s,%d",(*q).name,(*q).age);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序79】</font><br>
题目:字符串排序。<br>
1.程序分析:<br>
2.程序源代码:<br>
main()<br>
{<br>
char *str1[20],*str2[20],*str3[20];<br>
char swap();<br>
printf("please input three strings\n");<br>
scanf("%s",str1);<br>
scanf("%s",str2);<br>
scanf("%s",str3);<br>
if(strcmp(str1,str2)>0) swap(str1,str2);<br>
if(strcmp(str1,str3)>0) swap(str1,str3);<br>
if(strcmp(str2,str3)>0) swap(str2,str3);<br>
printf("after being sorted\n");<br>
printf("%s\n%s\n%s\n",str1,str2,str3);<br>
}<br>
char swap(p1,p2)<br>
char *p1,*p2;<br>
{<br>
char *p[20];<br>
strcpy(p,p1);strcpy(p1,p2);strcpy(p2,p);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序80】</font><br>
题目:海滩上有一堆桃子,五只猴子来分。第一只猴子把这堆桃子凭据分为五份,多了一个,这只<br>
猴子把多的一个扔入海中,拿走了一份。第二只猴子把剩下的桃子又平均分成五份,又多了<br>
一个,它同样把多的一个扔入海中,拿走了一份,第三、第四、第五只猴子都是这样做的,<br>
问海滩上原来最少有多少个桃子?<br>
1.程序分析:<br>
2.程序源代码:<br>
main()<br>
{int i,m,j,k,count;<br>
for(i=4;i<10000;i+=4)<br>
{ count=0;<br>
m=i;<br>
for(k=0;k<5;k++)<br>
{<br>
j=i/4*5+1;<br>
i=j;<br>
if(j%4==0)<br>
count++;<br>
else<br>
break;<br>
}<br>
i=m;<br>
if(count==4)<br>
{printf("%d\n",count);<br>
break;}<br>
}<br>
}</p>
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<li><font color=#0772B1>上篇文章</font>:<a href="list.asp?id=209">经典c程序100例==61--70</a>
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<li><font color=#0772B1>下篇文章</font>:<a href="list.asp?id=211">经典c程序100例==81--90 </a>
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<TD bgColor="#e6e6e6" width="50%">□- C程序百例热点文章</TD>
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1.<a href="list.asp?id=212" title="经典c程序100例==91--100" target=_top>
经典c程序100例==91--100
</a>[阅读:<font color=red>162367</font>]<br>
2.<a href="list.asp?id=203" title="经典c程序100例==1--10" target=_top>
经典c程序100例==1--10
</a>[阅读:<font color=red>92965</font>]<br>
3.<a href="list.asp?id=208" title="经典c程序100例==51--60" target=_top>
经典c程序100例==51--60
</a>[阅读:<font color=red>72882</font>]<br>
4.<a href="list.asp?id=204" title="经典c程序100例==11--20 " target=_top>
经典c程序100例==11--20
</a>[阅读:<font color=red>68462</font>]<br>
5.<a href="list.asp?id=211" title="经典c程序100例==81--90 " target=_top>
经典c程序100例==81--90
</a>[阅读:<font color=red>63316</font>]<br>
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<a href=list.asp?id=212>经典c程序100例==91--100</a><br>
<a href=list.asp?id=211>经典c程序100例==81--90 </a><br>
<a href=list.asp?id=210>经典c程序100例==71--80</a><br>
<a href=list.asp?id=209>经典c程序100例==61--70</a><br>
<a href=list.asp?id=208>经典c程序100例==51--60</a><br>
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<td width="87%" align=center> 辽宁省铁岭师专c语言研究中心 <u>杨志锋</u> 数学系 <u>杜博</u> </td>
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