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class=zi>点击“保存设置”按扭可使您本次阅读的整体设置（文字、字号、背景）得以保留，下次阅读时您就不必再重新设置，以符合您的阅读习惯。</TD></TR></TBODY></TABLE></TD></TR></TBODY></TABLE></DIV>
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<TD class=zi width=562 valign="middle"><b><font color="#ffffff">.:.:经典c程序100例==21--30:.:.</font></b></TD>
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<TD class=zi vAlign=center width=308 height=25><font size="2"> 文字
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背景
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<TD class=zi width=2 ><font size="2"> </font></TD>
<TD class=zi width=164><font size="2"> 人气指数：<font color="#FF0000">31372</font>
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<p><font color="#FF9933"><b><font size="5"> <font color="#3300CC">经典c程序100例==21--30</font></font></b></font></p>
<p><font color="#990000">【程序21】</font><br>
题目：猴子吃桃问题：猴子第一天摘下若干个桃子，当即吃了一半，还不瘾，又多吃了一个<br>
第二天早上又将剩下的桃子吃掉一半，又多吃了一个。以后每天早上都吃了前一天剩下<br>
的一半零一个。到第10天早上想再吃时，见只剩下一个桃子了。求第一天共摘了多少。<br>
1.程序分析：采取逆向思维的方法，从后往前推断。<br>
2.程序源代码：<br>
main()<br>
{<br>
int day,x1,x2;<br>
day=9;<br>
x2=1;<br>
while(day>0)<br>
{x1=(x2+1)*2;/*第一天的桃子数是第2天桃子数加1后的2倍*/<br>
x2=x1;<br>
day--;<br>
}<br>
printf("the total is %d\n",x1);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序22】</font><br>
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