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<TD class=zi width=562 valign="middle"><b><font color="#ffffff">.:.:经典c程序100例==31--40:.:.</font></b></TD>
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<p align="left"><font color="#FF9933"><b><font size="5"> <font color="#3300CC">经典c程序100例==31--40</font></font></b></font></p>
<p><font color="#990000">【程序31】</font><br>
题目:请输入星期几的第一个字母来判断一下是星期几,如果第一个字母一样,则继续<br>
判断第二个字母。<br>
1.程序分析:用情况语句比较好,如果第一个字母一样,则判断用情况语句或if语句判断第二个字母。<br>
2.程序源代码:<br>
#include <stdio.h><br>
void main()<br>
{<br>
char letter;<br>
printf("please input the first letter of someday\n");<br>
while ((letter=getch())!='Y')/*当所按字母为Y时才结束*/<br>
{ switch (letter)<br>
{case 'S':printf("please input second letter\n");<br>
if((letter=getch())=='a')<br>
printf("saturday\n");<br>
else if ((letter=getch())=='u')<br>
printf("sunday\n");<br>
else printf("data error\n");<br>
break;<br>
case 'F':printf("friday\n");break;<br>
case 'M':printf("monday\n");break;<br>
case 'T':printf("please input second letter\n");<br>
if((letter=getch())=='u')<br>
printf("tuesday\n");<br>
else if ((letter=getch())=='h')<br>
printf("thursday\n");<br>
else printf("data error\n");<br>
break;<br>
case 'W':printf("wednesday\n");break;<br>
default: printf("data error\n");<br>
}<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序32】</font><br>
题目:Press any key to change color, do you want to try it. Please hurry up!<br>
1.程序分析: <br>
2.程序源代码:<br>
#include <conio.h><br>
void main(void)<br>
{<br>
int color;<br>
for (color = 0; color < 8; color++)<br>
{ <br>
textbackground(color);/*设置文本的背景颜色*/<br>
cprintf("This is color %d\r\n", color);<br>
cprintf("Press any key to continue\r\n");<br>
getch();/*输入字符看不见*/<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序33】</font><br>
题目:学习gotoxy()与clrscr()函数 <br>
1.程序分析:<br>
2.程序源代码:<br>
#include <conio.h><br>
void main(void)<br>
{<br>
clrscr();/*清屏函数*/<br>
textbackground(2);<br>
gotoxy(1, 5);/*定位函数*/<br>
cprintf("Output at row 5 column 1\n");<br>
textbackground(3);<br>
gotoxy(20, 10);<br>
cprintf("Output at row 10 column 20\n");<br>
}<br>
==============================================================<br>
<font color="#990000">【程序34】</font><br>
题目:练习函数调用<br>
1. 程序分析: <br>
2.程序源代码:<br>
#include <stdio.h><br>
void hello_world(void)<br>
{<br>
printf("Hello, world!\n");<br>
}<br>
void three_hellos(void)<br>
{<br>
int counter;<br>
for (counter = 1; counter <= 3; counter++)<br>
hello_world();/*调用此函数*/<br>
}<br>
void main(void)<br>
{<br>
three_hellos();/*调用此函数*/<br>
}<br>
==============================================================<br>
<font color="#990000">【程序35】</font><br>
题目:文本颜色设置<br>
1.程序分析:<br>
2.程序源代码:<br>
#include <conio.h><br>
void main(void)<br>
{<br>
int color;<br>
for (color = 1; color < 16; color++)<br>
{<br>
textcolor(color);/*设置文本颜色*/<br>
cprintf("This is color %d\r\n", color);<br>
}<br>
textcolor(128 + 15);<br>
cprintf("This is blinking\r\n");<br>
}<br>
==============================================================<br>
<font color="#990000">【程序36】</font><br>
题目:求100之内的素数 <br>
1.程序分析:<br>
2.程序源代码:<br>
#include <stdio.h><br>
#include "math.h"<br>
#define N 101<br>
main()<br>
{<br>
int i,j,line,a[N];<br>
for(i=2;i<N;i++) a[i]=i;<br>
for(i=2;i<sqrt(N);i++)<br>
for(j=i+1;j<N;j++)<br>
{<br>
if(a[i]!=0&&a[j]!=0)<br>
if(a[j]%a[i]==0)<br>
a[j]=0;}<br>
printf("\n");<br>
for(i=2,line=0;i<N;i++)<br>
{<br>
if(a[i]!=0)<br>
{printf("%5d",a[i]);<br>
line++;}<br>
if(line==10)<br>
{printf("\n");<br>
line=0;}<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序37】</font><br>
题目:对10个数进行排序<br>
1.程序分析:可以利用选择法,即从后9个比较过程中,选择一个最小的与第一个元素交换,<br>
下次类推,即用第二个元素与后8个进行比较,并进行交换。 <br>
2.程序源代码:<br>
#define N 10<br>
main()<br>
{int i,j,min,tem,a[N];<br>
/*input data*/<br>
printf("please input ten num:\n");<br>
for(i=0;i<N;i++)<br>
{<br>
printf("a[%d]=",i);<br>
scanf("%d",&a[i]);}<br>
printf("\n");<br>
for(i=0;i<N;i++)<br>
printf("%5d",a[i]);<br>
printf("\n");<br>
/*sort ten num*/<br>
for(i=0;i<N-1;i++)<br>
{min=i;<br>
for(j=i+1;j<N;j++)<br>
if(a[min]>a[j]) min=j;<br>
tem=a[i];<br>
a[i]=a[min];<br>
a[min]=tem;<br>
}<br>
/*output data*/<br>
printf("After sorted \n");<br>
for(i=0;i<N;i++)<br>
printf("%5d",a[i]);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序38】</font><br>
题目:求一个3*3矩阵对角线元素之和 <br>
1.程序分析:利用双重for循环控制输入二维数组,再将a[i][i]累加后输出。<br>
2.程序源代码:<br>
main()<br>
{<br>
float a[3][3],sum=0;<br>
int i,j;<br>
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