subject_41875.htm

一些关于vc的问答

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序号：41875 发表者：风流骑士 发表日期：2003-05-30 02:23:50
<br>主题：谁知道如何产生随机的10到99间的整数,并可进一步对他们设定范围
<br>内容：谢谢
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回复者：gaolea 回复日期：2003-05-30 03:28:27
<br>内容：In C#, you can use the following function: Random(). This function generate number betweent 0--1. So you need time 100.&nbsp;&nbsp; Random()*100.<BR><BR>Ok?
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回复者：风流骑士 回复日期：2003-05-30 12:01:23
<br>内容：但这样产生的数是0到100之间的呀
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回复者：gaolea 回复日期：2003-05-30 21:30:32
<br>内容：Sorry. If you want to generate 10-99 integer, you need add some equations and if sentence. Such as if the number is less the 10, you should regenerate the number again. Is that right?
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回复者：风流骑士 回复日期：2003-05-30 21:33:31
<br>内容：但是在C++里好象不辨识Random()
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回复者：gaolea 回复日期：2003-05-30 22:25:55
<br>内容：you should include "math.h"
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回复者：风流骑士 回复日期：2003-05-31 02:21:18
<br>内容：好象不行,回头再试试.很感谢!
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<font color=red>答案被接受</font><br>回复者：试一试 回复日期：2003-05-31 03:07:25
<br>内容：按F1得到的<BR><BR><BR>/* RAND.C: This program seeds the random-number generator<BR> * with the time, then displays 10 random integers.<BR> */<BR><BR>#include &lt;stdlib.h&gt;<BR>#include &lt;stdio.h&gt;<BR>#include &lt;time.h&gt;<BR><BR>void main( void )<BR>{<BR>&nbsp;&nbsp; int i;<BR><BR>&nbsp;&nbsp; /* Seed the random-number generator with current time so that<BR>&nbsp;&nbsp;&nbsp;&nbsp;* the numbers will be different every time we run.<BR>&nbsp;&nbsp;&nbsp;&nbsp;*/<BR>&nbsp;&nbsp; srand( (unsigned)time( NULL ) );<BR><BR>&nbsp;&nbsp; /* Display 10 numbers. */<BR>&nbsp;&nbsp; for( i = 0;&nbsp;&nbsp; i &lt; 10;i++ )<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;printf( "&nbsp;&nbsp;%6d\n", rand() );<BR>}<BR><BR>Output<BR>&nbsp;&nbsp;&nbsp;&nbsp;6929<BR>&nbsp;&nbsp;&nbsp;&nbsp;8026<BR>&nbsp;&nbsp; 21987<BR>&nbsp;&nbsp; 30734<BR>&nbsp;&nbsp; 20587<BR>&nbsp;&nbsp;&nbsp;&nbsp;6699<BR>&nbsp;&nbsp; 22034<BR>&nbsp;&nbsp; 25051<BR>&nbsp;&nbsp;&nbsp;&nbsp;7988<BR>&nbsp;&nbsp; 10104<BR><BR>正经事如下<BR>&nbsp;&nbsp;&nbsp;&nbsp;while(true)<BR>&nbsp;&nbsp;&nbsp;&nbsp;{<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; srand( (unsigned)time( NULL ) );<BR><BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;int iRand = rand();<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;iRand %= 100;//先限制在0-100以内<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;if(iRand &gt; 10)<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;break;//再大于10的话，收工<BR>&nbsp;&nbsp;&nbsp;&nbsp;}<BR>
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回复者：yuzhixiang 回复日期：2003-05-31 13:06:42
<br>内容：//////////////////////////////////////////////////////////<BR>////Another method,insert following code<BR>&nbsp;&nbsp;int RndNum=10+89*((rand()%101)/100.0);<BR><BR>
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回复者：试一试 回复日期：2003-06-05 20:43:31
<br>内容：8楼朋友Good!
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回复者：timiil 回复日期：2003-06-05 21:48:49
<br>内容：不用这么烦吧。。。把分给我好过了。。。<BR>int myRND(int a,int b)<BR>{<BR>&nbsp;&nbsp;&nbsp;&nbsp;return b+(b-a)*random()<BR>}<BR><BR>返回(a,b)区间内的随机数
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回复者：试一试 回复日期：2003-06-05 22:19:22
<br>内容：不错！10楼兄弟，请教如何通过VC编译器？多谢！
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