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序号:27115 发表者:mm2003 发表日期:2003-01-08 16:07:35
<br>主题:谁有CRC校验的源码
<br>内容:谁有CRC校验的源码,请发给我,一定给分,谢谢!!
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回复者:bb 回复日期:2003-01-08 16:17:24
<br>内容:unsigned short CalCRC(char *buf, long count)<BR>{<BR>&nbsp;&nbsp; unsigned short crc;<BR>&nbsp;&nbsp; register i;<BR>&nbsp;&nbsp; unsigned char* ptr=(unsigned char*)buf;<BR>&nbsp;&nbsp; crc = 0;<BR>&nbsp;&nbsp; count --;&nbsp;&nbsp;<BR>&nbsp;&nbsp; while (count &gt;= 0) <BR>&nbsp;&nbsp; {<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;--count;<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;crc = crc ^ (unsigned short)*ptr &lt;&lt; 8;<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;ptr++;<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;for (i = 0; i &lt; 8; ++i)<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; if (crc &amp; 0x8000)<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;crc = crc &lt;&lt; 1 ^ 0x1021;<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; else<BR>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;crc = crc &lt;&lt; 1;<BR>&nbsp;&nbsp; }<BR>&nbsp;&nbsp; return (crc &amp; 0xFFFF);<BR>}
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回复者:mm2003 回复日期:2003-01-08 16:24:59
<br>内容:能否介绍一下它的原理再给分呢?
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