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序号：21305 发表者：李春宁 发表日期：2002-11-15 18:31:03
<br>主题：如何将CString对象转换为char *?
<br>内容：如何实现CString和char *的转换<BR><BR>
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<font color=red>答案被接受</font><br>回复者：linney 回复日期：2002-11-15 18:46:28
<br>内容：使用CString::GetBuffer（）方法可以拿到串的指针，拿到这个指针，呵呵，你想怎么都行：）
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回复者：李春宁 回复日期：2002-11-15 19:04:03
<br>内容：char cChar[512];<BR><BR>// CString转换为char*<BR>strcpy(cChar, strString.GetBuffer(0));<BR>strString.ReleaseBuffer();<BR><BR>为什么GetBuffer(0)和GetBuffer(3)结果都一样<BR><BR>GetBuffer的参数作用是什么?
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回复者：TheCold 回复日期：2002-11-15 19:11:51
<br>内容：You will need this mostly to pass a CString to a function that expects a char*. <BR>&nbsp;&nbsp; // Prototype of a function expecting a char*:<BR>&nbsp;&nbsp; void Foo(char *c);<BR>&nbsp;&nbsp; //...<BR>&nbsp;&nbsp; CString csMyString = "Hello World";<BR>&nbsp;&nbsp; //...now call Foo():<BR>&nbsp;&nbsp; char *str = csMyString.GetBuffer(csMyString.GetLength());<BR>&nbsp;&nbsp; Foo(str);<BR>&nbsp;&nbsp; // or directly:<BR>&nbsp;&nbsp; Foo(csMyString.GetBuffer(csMyString.GetLength()));<BR>&nbsp;&nbsp; // if Foo modifies the passed char*, you must call<BR>&nbsp;&nbsp; csMyString.ReleaseBuffer(-1);<BR><BR>Notes:<BR>a) CString::GetBuffer() will return a char* only in non-UNICODE builds. <BR>b) CString has an implicit 208 operator to LPCTSTR. In non-UNICODE builds, that is a const char*. Do not use a cast hack like this: <BR>&nbsp;&nbsp; Foo((char *)((LPCSTR)csMyString)); // BAD!!!!<BR><BR>c) Do not call any other CString member function on csMyString between GetBuffer() and ReleaseBuffer().<BR>
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