subject_26104.htm

一些关于vc的问答

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序号：26104 发表者：Jessica 发表日期：2002-12-28 21:30:50
<br>主题：请不吝赐教---可否定义多个互不干扰的定时器？
<br>内容：用settimer我只会定义一个定时器，怎样定义多个？？？<BR>拜托！帮帮忙！
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回复者：tjhe 回复日期：2002-12-28 21:47:35
<br>内容：多调用几次,每次不同的定时器ID,时间间隔,回调函数<BR>
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回复者：晚风也渡 回复日期：2002-12-29 13:00:28
<br>内容：SetTimer()函数原形UINT SetTimer( UINT nIDEvent, UINT nElapse, void (CALLBACK EXPORT* lpfnTimer)(HWND, UINT, UINT, DWORD) );<BR><BR>SetTimer(1,interval1,proc1);<BR>SetTimer(2,interval2,proc2);<BR>
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<font color=red>答案被接受</font><br>回复者：tigersky2000 回复日期：2002-12-29 15:12:40
<br>内容：你用SetTimer()定义时，可以将第一个参数定义成不同的ＩＤ<BR>然后，在ontimer中用<BR><BR>switch (wParam)<BR>{<BR>case 1:<BR>//todo: your work1<BR>break;<BR>case 2:<BR>//todo: your work2<BR>default:<BR>break;<BR>}<BR><BR>你也可以为不同的timer定义不同的回调函数，原型如下<BR>void CALLBACK TimeProc(<BR>&nbsp;&nbsp;UINT uID,&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<BR>&nbsp;&nbsp;UINT uMsg,&nbsp;&nbsp;&nbsp;&nbsp; <BR>&nbsp;&nbsp;DWORD dwUser,&nbsp;&nbsp;<BR>&nbsp;&nbsp;DWORD dw1,&nbsp;&nbsp;&nbsp;&nbsp; <BR>&nbsp;&nbsp;DWORD dw2&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<BR>);<BR> <BR>TimeProc is a placeholder for the application-defined function name. <BR><BR>Parameters<BR>uID <BR>Identifier of the timer event. This identifier was returned by the timeSetEvent function when the timer event was set up. <BR>uMsg <BR>Reserved; do not use. <BR>dwUser <BR>User instance data supplied to the dwUser parameter of timeSetEvent. <BR>dw1 and dw2 <BR>Reserved; do not use. <BR>Return Values<BR>This function does not return a value.<BR>
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