hannuotawenti.txt

来自「这是关于基本汉诺塔问题的一个算法」· 文本 代码 · 共 52 行

TXT
52
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*程序与程序注释
#include<stdio.h>
void movedisc(unsigned n,char fromneedle,char toneedle,char usingneedle);
int i=0;
void main()
{
   unsigned n;
   printf("please enter the number of disc:");
   scanf("%d",&n);               /*输入N值*/
   printf("\tneedle:\ta\t b\t c\n");
   movedisc(n,'a','c','b');        /*从A上借助B将N个盘子移动到C上*/
   printf("\t Total: %d\n",i);
}
void movedisc(unsigned n,char fromneedle,char toneedle,char usingneedle)
{
   if(n>0)
   {
      movedisc(n-1,fromneedle,usingneedle,toneedle);
                     /*从fromneedle上借助toneedle将N-1个盘子移动到usingneedle上*/
      ++i;
      switch(fromneedle)     /*将fromneedle 上的一个盘子移到toneedle上*/
      {
         case 'a': switch(toneedle)
                   {
                        case 'b': printf("\t[%d]:\t%2d.........>%2d\n",i,n,n);
                           break;
                        case 'c': printf("\t[%d]:\t%2d...............>%2d\n",i,n,n);
                           break;
                   }
                  break;
         case 'b': switch(toneedle)
                  {
                     case 'a': printf("\t[%d]:\t%2d<...............>%2d\n",i,n,n);
                        break;
                     case 'c': printf("\t[%d]:\t        %2d........>%2d\n",i,n,n);
                        break;
                  }
                  break;
         case 'c': switch(toneedle)
                  {
                     case 'a': printf("\t[%d]:\t%2d<............%2d\n",i,n,n);
                        break;
                     case 'b': printf("\t[%d]:\t%2d<........%2d\n",i,n,n);
                        break;
                  }
                  break;
         }
         movedisc(n-1,usingneedle,toneedle,fromneedle);
               /*从usingneedle上借助fromneedle将N-1个盘子移动到toneedle上*/
      }
}

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