dis.asm

来自「比dos下的debug更好的debug程序源码」· 汇编 代码 · 共 325 行

;
; GRDB
;
; Copyright(c) LADsoft
;
; David Lindauer, [e-mail]
;
;
; dis.asm
;
; Function: patch the dissassembly code together, display the output
;	handle disassembler commands
;
	;MASM MODE
	.model small
	.386

include  eprints.inc 
include  ioperand.inc
include  eoperand.inc 
include  iopcodes.inc
include  eopcodes.inc 
include  emtrap.inc 
include  einput.inc 
include  eoptions.inc

	PUBLIC	diss,DisOneLine

DEFAULTBYTES = 32		; max number of bytes/line (should be 16)

	.data

startingDisAddr	dw	0	;current disassembly address
endningDisAddr	dw	?	;end of disassembly
extraBytes	dw	0	;number of overflow bytes, e.g. if instruction
				;was more than five bytes we need more lines
DisassemblySeg	dw	0	;disassembly segment

	.code
	oldposition EQU bp - 4	;beginning of bytes for line
	put	EQU bp -6	;unused
	bytestomove EQU bp - 8	;number of bytes to put in hex dump portion
				;of line
;	.code

isNewLine	EQU	[bp-2]	;set to true if we are doing an overflow line
oldposition	EQU	[bp-4]	;beginning of bytes for line
put		EQU	[bp-6]	;unused
bytestomove	EQU	[bp-8]	;number of bytes to put in hex dump portion
				;of line

;
; Get a dissassembled line of code
; INPUT: DI points to 256-byte buffer in caller's stack frame
;	Remember that DS=SS during this process
;	SI appears to point to the code to disassemble
;
GetCodeLine	PROC	
	ENTER	8,0	       		;8 bytes of automatic space
	mov	WORD PTR isNewLine,TRUE ; Assume it has an opcode
	mov	BYTE PTR [di],0		; Clear output buffer
	mov	oldposition,si		; Current position
	test	extrabytes,0FFh		; See if still printing bytes
	jz	short notextra		; from last instruction

;Only 5 code bytes fit on a line before the mnemonics, so if this instruction
;had >5 bytes, we need to stick them on another line by themselves. In this
;case, we already snagged them, and I guess DI points to them.  So we add
;the number of additional bytes to our pointer to the input, then exchange
;this with the buffer pointer
;  The implication here is that the entire opcode has been disassembled
;and converted to mnemonics, but defninitely not clear yet just exactly
;where the extra opcode bytes get displayed.  Right here, we tab over to
;a new position and zero out the buffer beyond those bytes.

	add	si,extrabytes		; New position to edi
	xchg	si,di			;

;Now, SI points into the buffer at a location just past the extra bytes. We
;put a 0 into the buffer for reasons unknown right now, then call TabTo.
;AHA, TabTo calls strlen, which will return a string length of 0 since SI
;points to a 0, and therefore we get a full tab. TabTo stuffed the
;intervening positions with spaces, and terminated them with 0. But we
;overwrite that and the next 15 buffer positions with 0 anyway.

	mov	BYTE PTR [si],0		; Clear buffer
	mov	al,10			; Tab to pos 14
	call	TabTo			; by stuffing spaces into the buffer
	xchg	si,di			; edi = buffer again now
	push	di			;save buffer position
	mov	cx,4			; next four DWORDS = 0;
	sub	ax,ax			;
	rep	stosd			; Store the dwords
	pop	di			;and point at 16 0's
	mov	WORD PTR isNewLine,False; Doesn't have an opcode
	jmp	btm

;OK, we aren't doing leftover stuff from the prior call.

notextra:
	mov	ax,code_address		; Get code address
	cmp	ax,endningDisAddr			; See if done
	jnc	endcodeline		; Quit if nothing left
	xchg	si,di			; esi = buffer now
	push	esi			;save buffer address
	mov	ax,fs			;get segment
	call	putword			;build that into buffer
	mov	BYTE PTR [si],':'	; Print ':' in buffer
	inc	si			;go past the colon
	mov	ax,code_Address		; Get code address
	call	putword			; Print it out in buffer
	mov	BYTE PTR [si],' '	; Put a space
	inc	si			;go past the space
	mov	BYTE PTR [si],0		; Put an end-of-buffer
	pop	eax			;restore the buffer address into EAX
	xchg	esi,eax			;now put it into ESI, EAX has new ptr
	push	eax			;save new pointer
	mov	al,25                   ; Tab to pos 29
	call	TabTo			;stuff with spaces

;XCHG always gives me headaches.  Lets see... TabTo bumped SI up, while EAX
;still holds the buffer position before the spaces TabTo put in there.
;More important, the prior position is on the stack, since we are about to
;blow EAX at ReadOverrides. This old position (just after the offset) will
;eventually be popped into EDI.
;  Now DI points to the post-spaces position, and SI points to whatever DI
;pointed to.  This requires a careful trace, so:
;1) DI entered this routine pointing to the 256-byte buffer on the stack
;2) Then, it was exchanged, so DI pointed to the code to disassemble
;3) Now, di points back into the buffer and SI points to the code to dis

	xchg	si,di			; edi = buffer beyond spaces
	call	ReadOverrides		; Read any overrides
	call	FindOpcode		; Find the opcode table

;The prior two calls moved SI past this opcode, which was consumed and
;translated. NOW we point SI back into the buffer and DI at the code
;to disassemble.

	xchg	si,di			; esi = buffer, di=code
	jnc	short gotopcode		; Got opcode, go format the text

;If the opcode was unrecognised, we need to just DB this byte and try again
;to find the start of an opcode on the next byte until we are back into
;some kind of sync again.

	push	si			; Else just put a DB
	mov	ax,"db"			;opcode not in table, could be new
	call	put2			; CPU type
	pop	si			;restore position before 'db'
	mov	al,TAB_ARGPOS		; Tab to the arguments=12+4?
	call	TabTo			;stuff with spaces
	mov	al,fs:[di]		;Get next code byte into AL
	inc	di			;bump code pointer
	call	putbyte			;cvt to ASCII and stick in bufer
	mov	BYTE PTR [si],0		; End the buffer
	xchg	si,di			;DI=buffer, SI=code
	pop	edi			;address just past offset of address
	jmp	short btm		; Go do the byte dump

;If we got here, the opcode was recognized.  Right here:
;SI=buffer pointer, DI=code pointer

gotopcode:
	push	si			;save buffer pointer
	mov	si,di			;point SI at the code
	sub	ax,ax			; assume 16-bit disassembly
	call	DispatchOperands	;this probably bumps SI past them
	mov	di,si			;so DI is now the code pointer
	pop	si			;restore the buffer pointer
	push	di			;save the code pointer
	call	FormatDisassembly	;Use the operand parse to format output
	pop	di			;restore code pointer
	xchg	si,di			;SI now code, DI now bufer

;EAX, pushed far above, contained a pointer into the buffer just past the
;offset part of the address plus 1 space, and points at the 0 following
;that space.

	pop	edi			;but so what, since DI now restored
btm:

;We already put a 0 in this location way up above, but I guess it won't
;hurt to do it twice, just to make sure...

	mov	BYTE PTR [di],0		; End the buffer

;Ouch. Let's see... SI points to the code we are disassembling whether we
;found a valid opcode or not.  Probably coincidence.

	mov	ax,si			; Calculate number of bytes to dump
	sub	ax,oldposition		;by subtracting old from new offset
	mov	bytestomove,ax		;and set variable with result
	mov	extrabytes,0		; Bytes for next round = 0
	cmp	WORD PTR bytestomove,5	; See if > 5
	jbe	short notmultiline	; No, not multiline
	mov	ax,bytestomove		; Else calculate bytes left
	sub	al,5			;and save result for next time
	mov	extrabytes,ax	
	mov	WORD PTR bytestomove,5	; Dumping 5 bytes - our max
notmultiline:

;Ouch again. Lets see... SI points to the code, and DI to the buffer, so
;we switch them, DI=code and SI=buffer

	xchg	si,di			; esi = buffer
	push	di			; Save code pointer
 	mov	di,oldposition		; Get original code position
	mov	cx,bytestomove		; Get bytes to move
putlp:
	mov	al,fs:[di]		; Get a byte
	call	putbyte			; Expand to ASCII
	mov	BYTE PTR [si],' '	; Put in a space
	inc	si			; Next buffer pos
	inc	di			; Next code pos
	LOOP	putlp			; Loop till done
	xchg	si,di			; Restore regs DI=buf, SI=code
	mov	ax,bytestomove		; Codeaddress+=bytes dumped
	add	code_address,ax	
endcodeline:
	mov	ax,isNewLine		; Return new line flag
	LEAVE				
	ret
GetCodeLine	ENDP	
;
; Main disassembler
; The user pressed the U command key, followed by ???, then CR.  We are going 
; to disassemble from either where we are, or from the address provided.
;	My guess is that SI points to the input line at the character
; following the U.
;  
;
diss	PROC	
	ENTER	256,0			; Buffer = 256 bytes long
	call	crlf			; start on new line
	call	WadeSpace		; See if any parms
	jz	short atindex		; No disassemble at index
	call	ReadAddress		; Else read start address into BX
	jc	badargs			; Get out bad args
	mov	ax,DEFAULTBYTES		; Number of bytes to disassemble=32
	add	ax,bx			; Find end of disassembly
	jnc	okadd			; Seems to be a segment limit
      	mov	ax,0FFFFh		; goto end of segment?
okadd:
	mov	endningDisAddr,ax	; Save count? as default
	call	WadeSpace		; See if any more args
	jz	short gotargs		; No, got args
	call	ReadNumber		; Read the end address
	jc	short badargs           ; Out if bad args
	mov	endningDisAddr,ax			; Save end
	jmp	short gotargs		; We have args
badargs:
	stc				; Error
	LEAVE
	ret
atindex:
	mov	bx,startingDisAddr	; Get the next address to disassemble
	mov	dx,DisassemblySeg 	;
	mov	ax,DEFAULTBYTES		; Default bytes to disassemble
	add	ax,bx			;
	mov	endningDisAddr,ax 	; Set up end
gotargs:
	call	defCS			; get CS segment
	mov	code_address,bx		; Save code address for printout
	mov	si,bx			;
	mov	fs,dx			; ES = the seg
	mov	DisassemblySeg,fs		
gcloop:	
	call	scankey
	jnz	dusetadr
	lea	di,[bp - 256]		; Get the buffer
	call	GetCodeLine		; Get a line of text
	lea	bx,[bp - 256]		; Print out the text
	call	dgroupMessage
	call	crlf
	cmp	si,0fff0h
	jnc	dusetadr2
	cmp	si,endningDisAddr		
	jc	gcloop			; Loop if not
	test	extrabytes,0FFFFh	; Loop if not done with dump
	jnz	gcloop			
dusetadr:
	mov	si,code_address	
	mov	startingDisAddr,si		
	clc
	LEAVE
	ret
dusetadr2:
	sub	si,si
	mov	code_address,si
	jmp	dusetadr
diss	ENDP	
;
; Disassemble one line.  Used by the Reg display command
; INPUT: DX holds segment value (CS)
;	BS holds offset value (IP)
;
DisOneLine	PROC	
	ENTER	256,0			; Space for buffer
	push	bx		 	;save logical IP
	push	dx			;and logical CS
	call	crlf			;so CRLF won't blow them
	pop	dx
	pop	bx
	mov	ax,1			;move to next position		
	add	ax,bx			; One byte to disassemble
	mov	endningDisAddr,ax 	;(will disassemble entire instruction)
	mov	code_address,bx		;save this disassembly address
	mov	fs,dx			;save segment in FS
	mov	si,bx			;point to code to disassemble in SI
	mov	startingDisAddr,si	; Save new starting index
	mov	DisassemblySeg,fs 	;set disassembly segment
dol_loop:
	lea	di,[bp - 256]		;Point DI at buffer to dis into
	call	GetCodeLine		; Get a line of code
	lea	bx,[bp -256]		;point BX at line we created
	call	dgroupMessage		;and put it on the screen
	call	crlf			;down to the next line
	test	extrabytes,0FFFFh	; See if >5 opcode bytes
	jnz	dol_loop		; Loop if so
	clc				; No errors
	leave
	ret
DisOneLine	ENDP	
END