vec_rr.h

来自「数值算法库for Unix」· C头文件 代码 · 共 93 行

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#ifndef NTL_vec_RR__H#define NTL_vec_RR__H#include <NTL/RR.h>#include <NTL/vector.h>NTL_OPEN_NNSNTL_vector_decl(RR,vec_RR)NTL_eq_vector_decl(RR,vec_RR)NTL_io_vector_decl(RR,vec_RR)void mul(vec_RR& x, const vec_RR& a, const RR& b);inline void mul(vec_RR& x, const RR& a, const vec_RR& b)   { mul(x, b, a); }void mul(vec_RR& x, const vec_RR& a, double b);inline void mul(vec_RR& x, double a, const vec_RR& b)   { mul(x, b, a); }void add(vec_RR& x, const vec_RR& a, const vec_RR& b);void sub(vec_RR& x, const vec_RR& a, const vec_RR& b);void clear(vec_RR& x);void negate(vec_RR& x, const vec_RR& a);void InnerProduct(RR& x, const vec_RR& a, const vec_RR& b);long IsZero(const vec_RR& a);void VectorCopy(vec_RR& x, const vec_RR& a, long n);inline vec_RR VectorCopy(const vec_RR& a, long n)   { vec_RR x; VectorCopy(x, a, n); NTL_OPT_RETURN(vec_RR, x); } vec_RR operator+(const vec_RR& a, const vec_RR& b);vec_RR operator-(const vec_RR& a, const vec_RR& b);vec_RR operator-(const vec_RR& a);inline vec_RR operator*(const vec_RR& a, const RR& b)   { vec_RR x; mul(x, a, b); NTL_OPT_RETURN(vec_RR, x); }inline vec_RR operator*(const vec_RR& a, double b)   { vec_RR x; mul(x, a, b); NTL_OPT_RETURN(vec_RR, x); }inline vec_RR operator*(const RR& a, const vec_RR& b)   { vec_RR x; mul(x, a, b); NTL_OPT_RETURN(vec_RR, x); }inline vec_RR operator*(double a, const vec_RR& b)   { vec_RR x; mul(x, a, b); NTL_OPT_RETURN(vec_RR, x); }RR operator*(const vec_RR& a, const vec_RR& b);// assignment operator notation:inline vec_RR& operator+=(vec_RR& x, const vec_RR& a){    add(x, x, a);   return x;}inline vec_RR& operator-=(vec_RR& x, const vec_RR& a){    sub(x, x, a);   return x;}inline vec_RR& operator*=(vec_RR& x, const RR& a){    mul(x, x, a);   return x;}inline vec_RR& operator*=(vec_RR& x, double a){    mul(x, x, a);   return x;}NTL_CLOSE_NNS#endif

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