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📄 sort.sql.out

📁 关系型数据库 Postgresql 6.5.2
💻 OUT
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QUERY: create table s1 (x int4, y int4);QUERY: create table s2 (a int4, b int4, c int4);QUERY: insert into s1 values (1, 3);QUERY: insert into s1 values (2, 3);QUERY: insert into s1 values (2, 1);QUERY: insert into s2 values (1, 3, 9);QUERY: insert into s2 values (1, 4, 9);QUERY: insert into s2 values (3, 4, 7);QUERY: insert into s2 values (3, 5, 8);QUERY: select distinct y from s1;y  -- 1  3  QUERY: select a, c from s2;a  c  -- -- 1  9  1  9  3  7  3  8  QUERY: select distinct a, c from s2;a  c  -- -- 1  9  3  7  3  8  QUERY: select distinct a, c from s2 order by c;a  c  -- -- 3  7  3  8  1  9  QUERY: select b, c from s2 order by c, b;b  c  -- -- 4  7  5  8  3  9  4  9  QUERY: select x, b, c from s1, s2 order by b;x  b  c  -- -- -- 2  3  9  2  3  9  1  3  9  2  4  7  2  4  7  1  4  7  2  4  9  2  4  9  1  4  9  2  5  8  2  5  8  1  5  8  QUERY: select distinct a, x, c from s1, s2 order by c, x;a  x  c  -- -- -- 3  1  7  3  2  7  3  1  8  3  2  8  1  1  9  1  2  9  QUERY: select x AS p, b AS q, c AS r from s1, s2 order by p;p  q  r  -- -- -- 1  5  8  1  4  7  1  4  9  1  3  9  2  3  9  2  3  9  2  5  8  2  5  8  2  4  9  2  4  7  2  4  9  2  4  7  QUERY: select x AS p, b AS q, c AS r from s1, s2 order by q;p  q  r  -- -- -- 2  3  9  2  3  9  1  3  9  2  4  7  2  4  7  1  4  7  2  4  9  2  4  9  1  4  9  2  5  8  2  5  8  1  5  8  QUERY: select x AS p, b AS q, c AS r from s1, s2 order by r;p  q  r  -- -- -- 2  4  7  2  4  7  1  4  7  2  5  8  2  5  8  1  5  8  2  4  9  2  4  9  1  4  9  2  3  9  2  3  9  1  3  9  QUERY: select x AS p, b AS q, c AS r from s1, s2 order by p, r;p  q  r  -- -- -- 1  4  7  1  5  8  1  4  9  1  3  9  2  4  7  2  4  7  2  5  8  2  5  8  2  3  9  2  4  9  2  3  9  2  4  9  QUERY: select x AS p, b AS q, c AS r from s1, s2 order by q, r;p  q  r  -- -- -- 2  3  9  2  3  9  1  3  9  2  4  7  2  4  7  1  4  7  2  4  9  2  4  9  1  4  9  2  5  8  2  5  8  1  5  8  QUERY: select x AS p, b AS q, c AS r from s1, s2 order by q, p;p  q  r  -- -- -- 1  3  9  2  3  9  2  3  9  1  4  9  1  4  7  2  4  7  2  4  7  2  4  9  2  4  9  1  5  8  2  5  8  2  5  8  QUERY: create table s3 (x int4);QUERY: insert into s3 values (3);QUERY: insert into s3 values (4);QUERY: select * from s1, s3 order by x;x  y  x  -- -- -- 1  3  4  1  3  3  2  1  3  2  3  3  2  1  4  2  3  4  QUERY: select * from s3, s1 order by x;x  x  y  -- -- -- 3  2  1  3  2  3  3  1  3  4  2  3  4  1  3  4  2  1  QUERY: create table s4 (a int4, b int4, c int4, d int4, e int4, f int4, g int4, h int4, i int4);QUERY: insert into s4 values (1, 1, 1, 1, 1, 1, 1, 1, 2);QUERY: insert into s4 values (1, 1, 1, 1, 1, 1, 1, 1, 1);QUERY: insert into s4 values (1, 1, 1, 1, 1, 1, 1, 1, 3);QUERY: select * from s4 order by a, b, c, d, e, f, g, h;a  b  c  d  e  f  g  h  i  -- -- -- -- -- -- -- -- -- 1  1  1  1  1  1  1  1  3  1  1  1  1  1  1  1  1  1  1  1  1  1  1  1  1  1  2  QUERY: create table s5 (a int4, b int4);QUERY: insert into s5 values (1, 2);QUERY: insert into s5 values (1, 3);QUERY: insert into s5 values (1, 1);QUERY: insert into s5 values (2, 1);QUERY: insert into s5 values (2, 4);QUERY: insert into s5 values (2, 2);QUERY: select * from s5 order by a using <;a  b  -- -- 1  1  1  3  1  2  2  2  2  4  2  1  QUERY: select * from s5 order by a using >;a  b  -- -- 2  2  2  4  2  1  1  1  1  3  1  2  QUERY: select * from s5 order by a using >, b using <;a  b  -- -- 2  1  2  2  2  4  1  1  1  2  1  3  QUERY: select * from s5 order by a using >, b using >;a  b  -- -- 2  4  2  2  2  1  1  3  1  2  1  1  QUERY: drop table s1, s2, s3, s4, s5;

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