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📄 sort.sql

📁 关系型数据库 Postgresql 6.5.2
💻 SQL
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------------------------------------------------------------------------------- sort.sql---    test sorting------ Copyright (c) 1994-5, Regents of the University of California---- $Id: sort.sql,v 1.1.1.1 1996/07/09 06:22:30 scrappy Exp $-----------------------------------------------------------------------------create table s1 (x int4, y int4);create table s2 (a int4, b int4, c int4);insert into s1 values (1, 3);insert into s1 values (2, 3);insert into s1 values (2, 1);insert into s2 values (1, 3, 9);insert into s2 values (1, 4, 9);insert into s2 values (3, 4, 7);insert into s2 values (3, 5, 8);select distinct y from s1;select a, c from s2;select distinct a, c from s2;select distinct a, c from s2 order by c;select b, c from s2 order by c, b;select x, b, c from s1, s2 order by b;select distinct a, x, c from s1, s2 order by c, x;select x AS p, b AS q, c AS r from s1, s2 order by p;select x AS p, b AS q, c AS r from s1, s2 order by q;select x AS p, b AS q, c AS r from s1, s2 order by r;select x AS p, b AS q, c AS r from s1, s2 order by p, r;select x AS p, b AS q, c AS r from s1, s2 order by q, r;select x AS p, b AS q, c AS r from s1, s2 order by q, p;create table s3 (x int4);insert into s3 values (3);insert into s3 values (4);select * from s1, s3 order by x;select * from s3, s1 order by x;create table s4 (a int4, b int4, c int4, d int4, e int4, f int4, g int4, h int4, i int4);insert into s4 values (1, 1, 1, 1, 1, 1, 1, 1, 2);insert into s4 values (1, 1, 1, 1, 1, 1, 1, 1, 1);insert into s4 values (1, 1, 1, 1, 1, 1, 1, 1, 3);select * from s4 order by a, b, c, d, e, f, g, h;create table s5 (a int4, b int4);insert into s5 values (1, 2);insert into s5 values (1, 3);insert into s5 values (1, 1);insert into s5 values (2, 1);insert into s5 values (2, 4);insert into s5 values (2, 2);select * from s5 order by a using <;select * from s5 order by a using >;select * from s5 order by a using >, b using <;select * from s5 order by a using >, b using >;drop table s1, s2, s3, s4, s5;

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