数据结构课程设计 数据结构B+树 B+ tree Library
上传时间： 2013-12-31
上传用户：semi1981
The primary goal of MySQL and Java Developer’s Guide is to provide a comprehensive approach to writing code from a Java application to a MySQL database using the industry standard: JDBC. As you will see later in this Introduction, the chapter titles indicate what area of database connectivity and manipulation they cover. The chapters are ordered to reflect the JDBC specification, but we aren’t here to simply describe the specification.
标签： comprehensive Developer approach primary
上传时间： 2014-01-13
上传用户：lnnn30
SQL: A Beginner’s Guide is recommended for anyone trying to build a foundation in SQL programming. The book is designed specifically for those who are new or relatively new to SQL however, those of you who need a refresher in SQL will also find this book beneficial.Whether you’re an experienced programmer, have had some web development experience, are a database administrator, or are new to programming and databases, SQL: A Beginner’s Guide provides a strong foundation that will be useful to any of you wishing to learn more about SQL.
标签： recommended programming foundation SQL
上传时间： 2013-12-24
上传用户：Amygdala
给定两个集合A、B，集合内的任一元素x满足1 ≤ x ≤ 109，并且每个集合的元素个数不大于105。我们希望求出A、B之间的关系。 任 务 ：给定两个集合的描述，判断它们满足下列关系的哪一种： A是B的一个真子集，输出“A is a proper subset of B” B是A的一个真子集，输出“B is a proper subset of A” A和B是同一个集合，输出“A equals B” A和B的交集为空，输出“A and B are disjoint” 上述情况都不是，输出“I m confused!”
标签：
上传时间： 2017-03-15
上传用户：yulg
This routine calls the glpk library to solve a LP/MIP problem. A typical LP problem has following structure: [min|max] C x s.t. Ax ["="|"<="|">="] b {x <= UB} {x >= LB} The calling syntax is: [XMIN,FMIN,STATUS,EXTRA]=glpkmex(SENSE,C,A,B,CTYPE,LB,UB,... VARTYPE,PARAM,LPSOLVER,SAVE)
标签： problem following routine library
上传时间： 2014-12-01
上传用户：changeboy
本ppt介绍了多层C/S型数据库应用，多层数据库应用的结构，典型的三层C/S结构，B/S型数据库应用，典型的B/S结构（三层），结合三层C/S的B/S结构（四层），使用多层分布式应用结构的优势，高可靠性的多层分布式结构等方面的内容
上传时间： 2015-03-15
上传用户：songnanhua
* 高斯列主元素消去法求解矩阵方程AX=B,其中A是N*N的矩阵,B是N*M矩阵 * 输入: n----方阵A的行数 * a----矩阵A * m----矩阵B的列数 * b----矩阵B * 输出: det----矩阵A的行列式值 * a----A消元后的上三角矩阵 * b----矩阵方程的解X
上传时间： 2015-07-26
上传用户：xauthu
上下文无关文法（Context-Free Grammar, CFG）是一个4元组G=(V, T, S, P)，其中，V和T是不相交的有限集，S∈V，P是一组有限的产生式规则集，形如A→α，其中A∈V，且α∈(V∪T)*。V的元素称为非终结符，T的元素称为终结符，S是一个特殊的非终结符，称为文法开始符。 设G=(V, T, S, P)是一个CFG，则G产生的语言是所有可由G产生的字符串组成的集合，即L(G)={x∈T* | Sx}。一个语言L是上下文无关语言（Context-Free Language, CFL），当且仅当存在一个CFG G，使得L=L(G)。 *⇒ 例如，设文法G：S→AB A→aA|a B→bB|b 则L(G)={a^nb^m | n,m>=1} 其中非终结符都是大写字母，开始符都是S，终结符都是小写字母。
标签： Context-Free Grammar CFG
上传时间： 2013-12-10
上传用户：gaojiao1999
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
标签： represented integers group items
上传时间： 2016-01-17
上传用户：jeffery
(1) 、用下述两条具体规则和规则形式实现.设大写字母表示魔王语言的词汇 小写字母表示人的语言词汇 希腊字母表示可以用大写字母或小写字母代换的变量.魔王语言可含人的词汇. (2) 、B→tAdA A→sae (3) 、将魔王语言B(ehnxgz)B解释成人的语言.每个字母对应下列的语言.
上传时间： 2013-12-30
上传用户：ayfeixiao
